A chinook salmon needs to jump a waterfall that is 1.5 m high. If the fish starts from a distance of 1.00 m from the base of the
ledge over which the waterfall flows, find the x- and y- components of the initial velocity the salmon would need to reach the ledge at the top of its trajectory. Can the fish make this jump? ( A Chinook salmon can jump out of the water with a speed of 6.26m/s)
<span>let the fsh jump with initial velocity (u) in direction (angle p) with horizontal
it can cross and reach top of trajectory if its top height h = 1.5m and horizontal distance d = (1/2) Range --------------------------------------... let t be top height time at top height, vertical component of its velocity =0 vy = 0 = u sin p - gt t = u sin p/g h = [u sin p]*t - 0.5 g[t[^2 1.5 = u^2 sin^2 p/g - u^2 sin^2 p/2g u^2 sin^2 p/2g = 1.5 u^2 sin^2 p = 1.5*2*9.8 = 29.4 u sin p = 5.42 m/s >>>>>>>>>>>>>>> V-component ===================== t = HALF the time of flight d = (1/2) Range (R) = (1/2) [2 u^2 sin p cos p/g] 1 = u^2 sin p cos p/g u sin p * u cos p = 9.8 5.42 * u cos p = 9.8 u cos p = 1.81 m/s >>>>>>>>>>>>> H-component check>> u = sqrt[u^2 cos^2 p + u^2 sin^2 p] = 5.71 m/s u < less than fish's potential jump speed 6.26 m/s
Reflection is when light bounces off an object. If the surface is smooth and shiny, like glass, water or polished metal, the light will reflect at the same angle as it hit the surface. ... This is called diffuse reflection. Diffuse reflection is when light hits an object and reflects in lots of different directions.
