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Cerrena [4.2K]
3 years ago
15

What conditions must be present for a translational and rotational equilibrium of a rigid body?

Physics
1 answer:
zheka24 [161]3 years ago
5 0
If a rigid body is in translational and rotational equilibrium, then
1. The sum of all applied forces is zero.
2. The sum of all applied moments is zero.
3. There is no linear acceleration.
4. There is no rotational acceleration.

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Why do scientist use different types of models to represent compounds
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Because they are different they all show different traits.
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Describe three physical changes that occur in nature?
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Answer: Physical changes in nature could then be erosion in a mountain, the melting of snow, and a river freezing over from the cold. Since none of these changes affect the chemical composition of the mountain, the snow, or the river, they are physical changes.

Explanation:

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What from the following list of statements about vectors is definitely true? (section 3.3) The magnitude of a vector can be smal
Mashcka [7]

Answer:

"Magnitude of a vector can be zero only if all components of a vector are zero."

Explanation:

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"Magnitude of a vector is positive if it is directed in +x and negative if is is directed in -X direction."

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"Magnitude of a vector can be zero only if all components of a vector are zero."

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6 0
3 years ago
A student adds ice to 150 mL of water. She observes that the temperature of the water decreases after 10 minutes. Which statemen
Step2247 [10]

Answer:

3- kinetic energy was transferred from the water to the ice

Explanation:

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3 0
3 years ago
A child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a
kirill [66]

Answer:

θ = 13.16 °

Explanation:

Lets take mass of child = m

Initial velocity ,u= 1.1 m/s

Final velocity ,v=3.7 m/s

d= 22.5 m

The force due to gravity along the incline plane = m g sinθ

The friction force = (m g)/5

Now from work power energy

We know that

work done by all forces = change in kinetic energy

( m g sinθ - (m g)/5 ) d = 1/2 m v² - 1/2 m u²

(2  g sinθ - ( 2 g)/5 ) d = v² -  u²

take g = 10 m/s²

(20 sinθ - ( 20)/5 ) 22.5 = 3.7² -  1.1²

20 sinθ - 4 =12.48/22.5

θ = 13.16 °

5 0
3 years ago
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