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3 years ago

What conditions must be present for a translational and rotational equilibrium of a rigid body?

1 answer:

5 0

If a rigid body is in translational and rotational equilibrium, then
1. The sum of all applied forces is zero.
2. The sum of all applied moments is zero.
3. There is no linear acceleration.
4. There is no rotational acceleration.

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5. An undisturbed soil sample has a wet density of 2.5 Mg/m3 when the water content is 25%. The specific gravity of the soil par

Dima020 [189]

Answer:

The submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

Explanation:

Given;

wet density of soil sample = 2.5 Mg/m³ = 25 kN/m³

Specific gravity of solid particle = 2.7

The dry unit weight of soil;

$\gamma _d = \frac{\gamma _t}{1 +w} = \frac{25}{1+0.25} = 20 \ kN/m^3$

for undisturbed state, the volume of the soil is;

$V_s =\frac{\gamma _d}{G_s \gamma _w} = \frac{20}{2.7*9.81} = 0.76 \ m^3\\\\Void \ volume, V_v = 1-0.76 = 0.24 \ m^3$

$Void \ ratio, \ e = \frac{0.24}{0.76} = 0.32$

Submerged effective density is given as;

$\rho _b = \frac{\rho_w(\gamma_s -1)}{1+e}$

density of water (ρw) = 2.7 x 25 kN/m³ = 67.5 kN/m³, substitute this in the above equation;

$\rho _b = \frac{\rho_w(\gamma_s -1)}{1+e} = \frac{67.5(2.7 -1)}{1+0.32} = 86.93 \ kN/m^3$

Therefore, the submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

5 0

3 years ago

Identify properties of a human body system

IceJOKER [234]

Answer:

integumentary, skeletal, muscular, nervous, endocrine, cardiovascular, lymphatic, respiratory, digestive, urinary, and reproductive

Explanation:

and this is biology not physics

5 0

3 years ago

A caterpillar tries to climb straight up a wall a meter high, but for every 2 cm up it climbs, it slides down 1 cm. Eventually,

tiny-mole [99]

Answer:

Total displacement traveled = 298

Explanation:

According to the given information, to actually climb for 1 cm, the caterpillar has to travel for 3 cm (2 cm upwards and 1 cm downwards).

So in order to climb straight up a one meter (100 cm) high wall, it needs to travel for 99 × 3 = 297 cm.

Then after a little it can travel up another cm to reach the top.

Therefore, the total displacement traveled = 297 + 1 = 298 cm

5 0

3 years ago

Read 2 more answers

Brass is an alloy made from copper and zinc a 0.59 kg brass sample at 98.0 is dropped into 2.80 kg of water at 5.0 c if the equi

zhannawk [14.2K]

The specific heat capacity of brass would be ranked between 0 and infinity

3 0

3 years ago

Read 2 more answers

Future space rockets might propel themselves by firing laser beams, rather than exhaust gases, out the back. The acceleration wo

Nina [5.8K]

Answer:

Acceleration = 0.0282 m/s^2

Distance = 13.98 * 10^12 m

Explanation:

we will apply the energy theorem

work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )

where :

work done = p * t

= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J

( note : convert 1 year to seconds )

and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0

back to equation 1

473040000 * 10^6 = 1/2 mv^2

Vf^2 = 2(473040000 * 10^6 ) / 1200

∴ Vf = 887918.92 m/s

i) Determine how fast the rocket is ( acceleration of the rocket )

a = Vf / t

= 887918.92 / ( 1 year )

= 0.0282 m/s^2

ii) determine distance travelled by rocket

Vf^2 - Vi^2 = 2as

Vi = 0

hence ; Vf^2 = 2as

s ( distance ) = Vf^2 / ( 2a )

= ( 887918.92 )^2 / ( 2 * 0.0282 )

= 13.98 * 10^12 m

8 0

3 years ago