Formula : CaCl2
Eh hope this helps
Answer: 1. 33, 2. 264
Explanation: 66m= 6s so, to find the position at 3s you just need to take 66/2 = 33m cause 3 is half of 6. & for 2 you will take 66x4= 264m cause it took 4s multiply by the original 6s to get 24s. Answer: 1 is 33m and 2 is 264m
Answer:
The electric potential at the center of the meter stick is 54 KV.
Explanation:
Electric potential (V) is given as:
i.e V = 
Where: k is the Coulomb constant, q is the charge and r is the distance.
Given: q = 3.0 μC = 3.0 x
C, r = 0.5 m
So that,
V = 
= 
V = 54000
= 54 000 volts
The electric potential at the center of the meter stick is 54 KV.
Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
= 
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹