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Phoenix [80]
3 years ago
12

"Which missing item would complete this alpha decay reaction? "

Physics
2 answers:
Helga [31]3 years ago
7 0
Find the attachment below.

nalin [4]3 years ago
7 0
This is alpha decay not beta decay. 

<span>Fermium 257 decays by ALPHA decay into 253 Cf which has an atomic number of 98 </span>

<span>So your reaction is </span>

<span>257Fm --> 253Cf...+ 4He </span>
<span>100................98.........2 </span>


<span>Interestingly Californium does undergo beta decay. </span>

<span>253Cf ---> 253Es + e- </span>
<span>98...............99 </span>

<span>Hope this helps.</span>
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3) If a ball launched at an angle of 10.0 degrees above horizontal from an initial height of 1.50 meters has a final horizontal
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3 0
3 years ago
The dragster has a mass of 1.3 Mg and a center of mass at G. A parachute is attached at C provides a horizontal braking force of
adell [148]

Answer:

The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is  16.33 m/s²

Explanation:

The additional information to the question is embedded in the diagram attached below:

The height between the dragster and ground is considered to be 0.35 m since is not given ; thus in addition win 0.75 m between the dragster and the parachute; we have: (0.75 + 0.35) m = 1.1 m

Balancing the equilibrium about point A;

F(1.1) - mg (1.25) = ma_a (0.35)

1.8v^2(1.1) - 1200(9.8)(1.25) = 1200a(0.35)

1.8v^2(1.1) - 14700 = 420 a   ------- equation (1)

F_x = ma_x \\ \\ = 1.8v^2 = 1200 \ a             --------- equation (2)

Replacing equation 2 into equation 1 ; we have :

{1.1 * 1200 \ a} - 14700 = 420 a

1320 a - 14700 = 420 a

1320 a -  420 a =14700

900 a = 14700

a = 14700/900

a = 16.33 m/s²

The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is  16.33 m/s²

5 0
3 years ago
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