Answer:
a
b
Explanation:
From the question we are told that
The initial position of the particle is
The initial velocity of the particle is
The acceleration is
The time duration is
Generally from kinematic equation
=>
=>
Generally from kinematic equation
Here s is the distance covered by the particle, so
=>
Generally the final position of the particle is
=>
=>
Answer:
Explanation:
This problem can be solved using the Third Kepler’s Law of Planetary motion:
<em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>
<em />
This law states a relation between the orbital period of a body (the exoplanet in this case) orbiting a greater body in space (the star in this case) with the size
of its orbit:
(1)
Where:
is the period of the orbit of the exoplanet (considering
)
is the Gravitational Constant and its value is
is the mass of the star
is orbital radius of the orbit the exoplanet describes around its star.
Now, if we want to find the radius, we have to rewrite (1) as:
(2)
(3)
Finally:
This is the radius of the exoplanet's orbit