Due to the gravitational pull of earth the asteroid would be pulled towards earth, so the answer is B.
Using the formula:
w = m x g ....... eq1
here w is weight of the object.
m is mass of the object, and
g is the acceleration of gravity.
mass, m = 14 lbm (given)
acceleration of gravity, g= 32.0 ft/
Now, substituting the values in equation (1):
w = 14lbm x 32.0 ft/ = 448 lbm ft/
since, 1 lbf = 32.174 lbm ft/
so, w = 448 x
w = 13.924lbf
Hence, the mass of an object is 13.924 lbf.
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<span>Displacement of the oscillator can be expressed in the mathematical form as:
x(t) = A*cos (ωt + δ),
therefore acceleration would be represented as => a = ¨x = â’ω^2*A*cos (ωt + δ),
the maximum acceleration will happen when the cosine is -1.
Hence, maximum acceleration => a-max = A*ω^2
The force associated with acceleration is F = ma.
Therefore maximum amplitude is
A = F / (m*ω^2)
= F / (4Ď€^2 * m * f^2) where f is the frequency of oscillation.
putting values in above equation we ge:
A = 50000 / 4Ď€^2 * 10^â’4 Ă— (10^6)^2
= 1.25 * 10^â’5
hence 1.25 * 10^-5 m/s^2</span>
Why don't you try using the following kinematics formula
Vf^2 = Vi^2 + 2ad
Then solve for d, distance.