the balanced equation is CH4 + 2O2 -> CO2 + 2H20
moles = mass ÷ mr
moles of methane = 10 ÷ 16
= 10/16
= 5/8 moles
the moles of carbon dioxide are the same as methane because the ratio is 1:1
mass = moles × Mr
mass of carbon dioxide = 5/8 × 44
= 220 ÷ 8
= 27.5 grams
to find out whether it obeys the law of conservation of mass, you must find the mass of the reactants and the mass of the products. if they are the same, it obeys the law of conservation of mass. otherwise it doesnt.
the mass of oxygen is 32 × 5/8
= 160/8
= 20g
we already have the mass of methane (10g) so add it on
mass of reactants = 20 + 10 = 30g
find mass of water: 5/8 × 18
= 90/8
= 11.25g
mass of products = 11.25 + 27.5 = 38.75g
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