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Chemistry

1 answer:

luda_lava [24]3 years ago

6 0

the balanced equation is CH4 + 2O2 -> CO2 + 2H20

moles = mass ÷ mr

moles of methane = 10 ÷ 16

= 10/16

= 5/8 moles

the moles of carbon dioxide are the same as methane because the ratio is 1:1

mass = moles × Mr

mass of carbon dioxide = 5/8 × 44

= 220 ÷ 8

= 27.5 grams

to find out whether it obeys the law of conservation of mass, you must find the mass of the reactants and the mass of the products. if they are the same, it obeys the law of conservation of mass. otherwise it doesnt.

the mass of oxygen is 32 × 5/8

= 160/8

= 20g

we already have the mass of methane (10g) so add it on

mass of reactants = 20 + 10 = 30g

find mass of water: 5/8 × 18

= 90/8

= 11.25g

mass of products = 11.25 + 27.5 = 38.75g

the mass of reactants vs products are not the same so it does not obey the law of conservation of mass

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A certain substance, X, has a triple-point temperature of 20°C at a pressure of 2.0 atm.

nikitadnepr [17]

Answer: The statement which could possibly not be true is C -" Liquid X can exist as a stable phase at 25°C, 1atm."

Explanation:

Triple point is the point where a substance co-exist as solid liquid and gas. At any point other than the triple point, the substance exist as a single phase substance.

As shown in the diagram, Liquid cannot exist as a stable phase at 1atm( below the the triple point pressure of 2atm) as the liquid can only exist beyond the pressure of triple point.