A (pretty sure) PLEASE MAKE ME BRAINLIEST
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Answer:
m AgCl = 28.395 g
Explanation:
- AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
∴ [AgNO3] = 0.156 mol/L
∴ V = 1.27L
⇒ mol AgNO3 = 0.156 mol/L * 1.27 L = 0.19812 mol AgNO3
mass AgCL:
⇒ m AgCl = 0.19812 mol AgNO3 * mol AgCl/molAgNO3 * 143.32gAgCl/molAgCl
⇒ m AgCl = 28.395 g
Answer:
Is this an actual question that you had for school?
Explanation:
