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dedylja [7]
3 years ago
9

Answer to A please! ASAP

Chemistry
1 answer:
Tanya [424]3 years ago
5 0
The answer is electron
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The decomposition of water into hydrogen gas Hy and oxygen gas Oz can be modeled by the balanced chemical equation
ASHA 777 [7]

Answer:

D. ) 2H2O - 2H2 + O2

3 0
2 years ago
BRAINLIEST:
vekshin1
33 is the correct answer
8 0
2 years ago
How many molecules of N204 are in 85.0 g of N2O4?
alukav5142 [94]

Answer:

5.56 × 10^23 molecules

Explanation:

The number of molecules in a molecule can be calculated by multiplying the number of moles in that molecule by Avagadro's number (6.02 × 10^23)

Using mole = mass/molar mass

Molar mass of N2O4 = 14(2) + 16(4)

= 28 + 64

= 92g/mol

mole = 85.0/92

= 0.9239

= 0.924mol

number of molecules of N2O4 (nA) = 0.924 × 6.02 × 10^23

= 5.56 × 10^23 molecules

4 0
3 years ago
Which of these is a covalent compound?<br><br> A. LiCl<br> B. MgO<br> C. AlCl3<br> D. CO
Fiesta28 [93]

Answer:

C. AlCl3 is a covalent compound.

Explanation:

It is formed by mutual sharing of electrons between two atoms each contributing equal number of electrons to the electron pair.

3 0
3 years ago
People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m
Llana [10]

Answer:

V_{HCl}=0.208L=208mL

Explanation:

Hello,

In this case, since the chemical reaction is:

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

n_{HCl}=2*n_{Mg(OH)_2}

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g}  =0.00858mol

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M

Then, since the concentration and the volume define the moles, we can write:

[HCl]*V_{HCl}=2*n_{Mg(OH)_2}

Therefore, the neutralized volume turns out:

V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL

Best regards.

3 0
2 years ago
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