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Sonja [21]
3 years ago
8

Please answer correctly nobody answers questions like this on brainly. BTW ITS STEM.

Chemistry
1 answer:
azamat3 years ago
6 0

Answer:

I believe your answer is B. Experimental research may lead to understanding descriptive research.

Generally, experimental research is a trial and error method that tests the hypothesis of descriptive research. Descriptive research being the theoretical or studied characters of a topic.

Please let me know if I had this wrong, and I'll do some extra research for you.

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Campare how the structure and function of a plant is similar to the human body
eimsori [14]
It is simple. A plant structure have different parts but both structures carry around an Cell Wall.
8 0
3 years ago
A patient is prescribed 100.0 mg/day of antibiotic for
Rufina [12.5K]

Answer:

70

Explanation:

20 x 5 vials = 100mg

therefore 5 vials required each day.

Two weeks = 14 days

14 days x 5 vials = 70 vials

4 0
3 years ago
How many grams of molybdenum(Mo) are in 2.68E24 atoms of Mo?
loris [4]
<h3>Answer:</h3>

427 g Mo

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

<u>Step 3: Convert</u>

<u />2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \  Mo} ) = 426.966 g Mo

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

426.966 g Mo ≈ 427 g Mo

3 0
3 years ago
Determine the molar mass of carbon.
Nimfa-mama [501]

Answer:

12.0107 g/mol

Explanation:

Hope this helps <3

3 0
3 years ago
In the following reaction, how many grams of lead(II) nitrate Pb(NO3)2 will produce 425 grams of sodium nitrate (NaNO3)? Pb(NO3)
KonstantinChe [14]
The answer is 828.03 grams.
8 0
4 years ago
Read 2 more answers
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