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Sonja [21]
3 years ago
8

Please answer correctly nobody answers questions like this on brainly. BTW ITS STEM.

Chemistry
1 answer:
azamat3 years ago
6 0

Answer:

I believe your answer is B. Experimental research may lead to understanding descriptive research.

Generally, experimental research is a trial and error method that tests the hypothesis of descriptive research. Descriptive research being the theoretical or studied characters of a topic.

Please let me know if I had this wrong, and I'll do some extra research for you.

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what happens when a gas obtained by heating Ammonium Chloride and slaked lime are passed through copper sulphate ?​
gogolik [260]

Answer:

Consequently, what happens when gas obtained by heating slaked lime and ammonium chloride is passed through copper sulphate solution? The HCl in the gas mixture will form hydrochloric and the H+ will react with some of the NH3(aq), forming NH4^+, and with some of the SO4^2-, forming HSO4^-.

8 0
3 years ago
CuCl2 + NaNO3 -------> Cu(NO3)2 + NaCl
pav-90 [236]

Answer:

what

Explanation:

3 0
3 years ago
What is 108 g +10+5+3
natali 33 [55]

ANSWER : 108 + 10 = 118

118 + ( 5 + 3 )

118 + 8 = <u>1</u><u>2</u><u>6</u>

<u>=</u><u> </u><u>1</u><u>2</u><u>6</u><u> </u><u>g</u>

7 0
3 years ago
Write and balance the chemical equation for the reaction associated with ΔHof of Li3N(s). What is the sum of all of the coeffici
ivann1987 [24]

Explanation:

In this reaction, the reactants are Li and N2. The product is Li3N

So we have;

Li + N2 → Li3N

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5 0
3 years ago
An antacid tablet with an active ingredient of CaCO3 was dissolved in 50.0 mL of 0.300 M HCl. When this solution was titrated wi
yaroslaw [1]

Answer:

Explanation:

mole of HCl remaining after reaction with CaCO₃

= .3 M of NaOH of 32.47 mL

= .3 x .03247 moles

= .009741 moles

Initial HCl taken = .3 x .005 moles = .0015 moles

Moles of HCl reacted with CaCO₃

= .009741 - .0015 = .008241 moles

CaCO₃     +    2HCl   =   CaCl₂  +  CO₂  +  H₂O .

1 mole        2 moles

2 moles of HCl reacts with 1 mole of  CaCO₃

.008241 moles of HCl reacts with .5 x .008241 moles of  CaCO₃

CaCO₃ reacted with HCl =  .5 x .008241 = .00412 moles

the mass (in grams) of calcium carbonate in the tablet

= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )

5 0
3 years ago
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