What happens when you sit in a chair?

Question 7 of 10 What is cos(22")? O A. 0.93 B. 0.22 C. 0.37 O D. 0.40

Goshia [24]

Answer:

c

Explanation:

3 0

3 years ago

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While an object is moving at a constant 20 m/s, a 5 N forcepushes the object to the left. At the same time, a 5 N force ispushin

Nostrana [21]

Answer: 20m/s.

Explanation:

Remember the second Newton's law:

F = a*m

This is:

The net force acting on an object is equal to the mass of the object times the acceleration of the object.

In this case, we have a force of 5N pushing the object to the right.

We also have a force of 5N pushing the object to the left.

These forces act on opposite directions.

Then the net force will be equal to the difference of these forces, this is:

F = 5N - 5N = 0N

Then the net force is 0N, then we have:

0N = m*a

0N/m = 0m/s^2 = a

This means that the acceleration of the object is 0, then the velocity of the object does not change.

This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)

5 0

3 years ago

If a textbook weighs 37.2 N on Venus, and the book has a mass of 4.4 kg, what is the strength of gravity on Venus?

Romashka [77]

$F=ma$

Where F is force, m is mass and a is acceleration.

$37.2N=4.4kg\cdot a\Longrightarrow a=\dfrac{37.2N}{4.4kg}=\boxed{8.45\dfrac{m}{s^2}}$

Hope this helps.

r3t40

4 0

3 years ago

Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t

Troyanec [42]

Answer:

The minimum coefficient of static friction for the box on the floor of the trunk is 0.54.

Explanation:

Given that,

Radius of the unbanked curve, r = 48 m

The speed of the car on the curve, v = 16 m/s

We need to find the minimum coefficient of static friction for the box on the floor of the trunk. It can be calculated by balancing the centripetal force and the force of gravity as :

$\mu mg=\dfrac{mv^2}{r}$

$\mu=\dfrac{v^2}{rg}$

$\mu=\dfrac{(16)^2}{48\times 9.8}$

$\mu=0.54$

So, the minimum coefficient of static friction for the box on the floor of the trunk is 0.54. Hence, this is the required solution.

5 0

4 years ago

Under what conditions might a stream's volume increase, and under what conditions might it decrease? How would the size of the s

JulijaS [17]

The volume of the stream would increase when it was raining and would decrease when there hadn't been rain, not necessarily a drought but just no rain for a while. As far as the sediment particles part they would be slightly bigger because there would be less water for them to mix into causing them to join together.

8 0

3 years ago