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zysi [14]
3 years ago
14

Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16% Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%. Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%. Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%Suppose you have a mean = 12 and a standard deviation = 3. What is the probability that a data member, x, is above 18?

A) 34%

B) 2.5%

C) 5%,

D) 16%

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Using a system of equations, it is found that one large jar holds 6 ounces and one small jar holds 4 ounces.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable l: Weight that a large jar holds.
  • Variable s: Weight that a small jar holds.

One large jar and five small jars can hold 26 ounces of jam, hence:

l + 5s = 26, which is the first equation in matrix form.

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l = 26 - 5s.

One large jar minus one small jar can hold 2 ounces of jam, hence:

l - s = 2, which is the second equation in matrix form:

Then:

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