Question

Need help w log expressions! pre cal! ILL MARK U BRAINLIST

Answer 1

Answer:

$log_{3}4 +6log_{3} {x}+log_{3} y$

Step-by-step explanation:

Mistake $6log_3(4xy)$

Correct expansion would be as given below:

$log_{3}(4 {x}^{6}y ) \\ \\ = log_{3}4 +log_{3} {x}^{6} +log_{3} y \\ \\ = log_{3}4 +6log_{3} {x}+log_{3} y$