Answer:
A) Oxidized
B) Reduced
C) Oxidized
D) Oxidized
Explanation:
A) Cu becomes Cu²⁺
oxidation state increased from 0 to +2. It gets oxidize.
B) Sn⁺⁴ becomes Sn²⁺
oxidation state decreased from +4 to +2. It gets reduced.
C) Cr³⁺ becomes Cr⁺⁶
oxidation state increased from +3 to +6. It gets oxidize.
D) Ag becomes Ag⁺
oxidation state increased from 0 to +1. It gets oxidize.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
<em>Consider the following reactions.
</em>
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Answer:
Arrow should be yeilds, THE COEFFICIENTS are mole ratios. So every 4 moles of NH3 or ammonia produce 6 moles of H2O water
The answer is False for sodium bromide it would be NaBr
Answer:
Bohr's model
Explanation:
Rutherford's experimental evidence best supports the Bohr's model. Recall that in the Bohr's model, the Rutherford model was regarded as a fundamental stepping stone.
Experimental evidence from the Bohr's model shows that the atom is not a sphere of positive charges in which negative charges were embedded. It would have been impossible for Neils Bohr to build the quantum theory from such a model.
Hence, the nuclear theory of Rutherford provided a fundamental stepping stone and experimental backup for the Bohr's model of the atom.
All other models mentioned in task 1 (Dalton, Thompson and Bohr) all mention the fact that the atom is made of particles. Thompson effectively described the particles as negative and positive in nature. Bohr took the idea further by proposing that the negative particles (electrons) were actually found in energy levels that are quantized.
