Question

4. (10 points) From the given triangle:

Answer 1

Answer:

sinθ =  y/r        sinθ = $\frac{-6}{10} = \frac{-3}{5}$

cosθ =  x/r       cosθ = $\frac{8}{10} = \frac{4}{5}$

tanθ =  y/x       tanθ =  $\frac{-6}{8} =\frac{-3}{4}$

cscθ =  r/y       cscθ = $\frac{-5}{3}$

secθ =  r/x       secθ =  $\frac{5}{4}$

cotθ = x/y       cotθ = $\frac{4}{3}$

explanation:

r = $\sqrt{(8)^{2}+(-6)^{2} }$

r = 10

x = 8

y = -6

r = $\sqrt{(4)^{2}+(3)^{2} }$

r = 5

x = 4

y = 3