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professor190 [17]

3 years ago

11

Rotation of players should be done how?

2 answers:

Gennadij [26K]3 years ago

6 0

Answer:

Clockwise movement

Explanation:

Players rotate “clockwise” through each of these positions. Another way to remember it is the player in 1 serves first, the player in 2 serves next, the player in 3 serves third, and so on. The order of rotation is set at the beginning of the game and maintained throughout the game (excepting substitutions).

Hope this helps!! :))

kumpel [21]3 years ago

5 0

Clockwise movement sorry if some else comment I can’t see the comment

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A box of spherical jawbreaker candies is 23 g and its volume is 32.3 cm3. If the average mass of a single jawbreaker is 0.94 g,

Alex777 [14]

The radius of each jawbreaker is approximately 0.68 cm.

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v = 4 /3 πr³

where

r = radius

Therefore,

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cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

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r³ = 0.31533683707

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3 years ago

Which occurs when a wave is reflected

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4 years ago

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A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9

Black_prince [1.1K]

Answer:

$C = 46.891 \mu F$

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

$s = \frac{P}{P.F} < COS^{-1} 0.65$

$S = \frac{1250}{0.65} < 49.45$

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

$P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]$

solving for $Q_{new}$

$Q_{new} = P tan [cos^{-1} P.F new]$

$Q_{new} = 1250 [tan[cos^{-1}0.9]]$

$Q_{new} = 605.40 VARS$

$Q_C = Q - Q_{new}$

$Q_C = 1461 - 605.4 = 855.6 vars$

$Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C$

$C = \frac{Q_C}{ v_{rms}^2 \omega}$

$C = \frac{855.6}{220^2 \times 2\pi \times 60}$

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