Ask question

Ask question

All categories

3 years ago

8

Leon uses a pressure gauge to measure the air pressure in one of his car tires. The gauge shows that the pressure is 220 kilopas

cals. The temperature is 297 K, and the outdoor air is at standard pressure. If the tire contains 4.8 moles of air, what is the volume of the tire? The volume of the car tire is __ liters.

2 answers:

ollegr [7]3 years ago

4 0

Answer:

The volume of the car tire is 53.93 Liters.

Explanation:

Pressure of the gas in car tire = $P=220kPa=2.17 atm$

(1 kPa = 0.009869 atm)

Temperature of the gas in tire =T = 297 K

Moles of air in the tire = n = 4.8 moles

Volume of the gas in the tire= V

Using an ideal gas equation:

$PV=nRT$

$V=\frac{nRT}{P}=\frac{4.8 mol\times 0.0821 atm L/mol K\times 297 K}{2.17 atm}$

V = 53.93 L

The volume of the car tire is 53.93 Liters.

mamaluj [8]3 years ago

3 0

Answer:

53.8 L

Explanation:

Ideal gas law

PV=nRT

must be for volume so we arrange to V=nRT/P

V= (4.8)(8.31)(297)/220

You might be interested in

How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?

Ksenya-84 [330]

Answer:

a. Approximately $1.3\; \rm mL$ .

b. Approximately $7.2\; \rm mL$ .

Explanation:

The unit of concentration " $\rm M$ " is equivalent to " $\rm mol \cdot L^{-1}$ ", which means "moles per liter."

However, the volume of both solutions were given in mililiters $\rm mL$ . Convert these volumes to liters:

$\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L$ .

$\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L$ .

In a solution of volume $V$ where the concentration of a solute is $c$ , there would be $c \cdot V$ (moles of) formula units of this solute.

Calculate the number of moles of $\rm NaCl$ formula units in each of the two solutions:

Solution in a.:

$n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol$ .

Solution in b.:

$n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol$ .

What volume of that $3.4\; \rm M$ (same as $3.4 \; \rm mol \cdot L^{-1}$ ) $\rm NaCl$ solution would contain that many

For the solution in a.:

$\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL$ .

Similarly, for the solution in b.:

$\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL$ .

8 0

3 years ago

Which element is being represented by the electron configuration below? [Ar] 4s2 3d3

Nina [5.8K]

Answer:
chromium (Cr)

4 0

3 years ago

Distinguish between zinc nitrate and lead nitrate

Kobotan [32]

Answer:

Zinc nitrate gives white ppt. which dissolves in excess ammonium hydroxide and produce a colorless solution whereas lead nitrate gives a chalky white ppt. of lead hydroxide which doesnot dissolve.

Explanation:

Hope this helps :)

7 0

3 years ago

The pot shown in the picture is made of two different metals. Why is the handle made of a different metal than the rest of the p

sertanlavr [38]

The rest of the bot needs to be able to heat up to cook ur food but the handles should be cooler so u can touch them

8 0

3 years ago

Read 2 more answers

Which characteristic could distinguish a crystalline solid from an amorphous

Mrac [35]

Answer:

The way it breaks

Explanation:

a-p-e-x

8 0

3 years ago