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oee [108]
3 years ago
8

Leon uses a pressure gauge to measure the air pressure in one of his car tires. The gauge shows that the pressure is 220 kilopas

cals. The temperature is 297 K, and the outdoor air is at standard pressure. If the tire contains 4.8 moles of air, what is the volume of the tire? The volume of the car tire is __ liters.
Chemistry
2 answers:
ollegr [7]3 years ago
4 0

Answer:

The volume of the car tire is 53.93 Liters.

Explanation:

Pressure of the gas in car tire =P=220kPa=2.17 atm

(1 kPa = 0.009869 atm)

Temperature of the gas in tire =T = 297 K

Moles of air in the tire = n = 4.8 moles

Volume of the gas in the tire= V

Using an ideal gas equation:

PV=nRT

V=\frac{nRT}{P}=\frac{4.8 mol\times 0.0821 atm L/mol K\times 297 K}{2.17 atm}

V = 53.93 L

The volume of the car tire is 53.93 Liters.

mamaluj [8]3 years ago
3 0

Answer:

53.8 L

Explanation:

Ideal gas law

PV=nRT

must be for volume so we arrange to V=nRT/P

V= (4.8)(8.31)(297)/220

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Gnoma [55]

Ionization Trend: First ionization energy will increase left to right across a period and increase bottom to top of a family (column).

A) Sr, Be, Mg are all in column 2 of the periodic table. Based on the first ionization rule above, from increasing to decreasing energy, the order is: Be, Mg, Sr

B) Bi, Cs, Ba are all in the same row of the periodic table. Based on the first ionization rule above, from increasing to decreasing energy, the order is: Bi, Ba, Cs

C) Same rule as above. Order is: Na, Al, S

8 0
3 years ago
Fill in the following information for the element
e-lub [12.9K]

Answer:

Period: 6 block

Group: f block

Family: Lanthanides

5 0
3 years ago
Read 2 more answers
A balloon filled with air has a volume of 6.50 L, a pressure of 0.900 atm, and a temperature of 25.0oC. If it is left out overni
kari74 [83]

Answer:

4.92 L

Explanation:

Rearrange ideal gas law and solve.

Change C to K.

- Hope that helps! Please let me know if you need further explanation.

8 0
3 years ago
1) Determine a fórmula da base hidróxido de bário: * 1 ponto a) b) c) d) 2) As bases são substâncias iônicas, ou seja, quando sã
Reika [66]

Answer:

1) Ba(OH)₂

2) The correct option is a) they conduct electricity.

Explanation:

To deduce the formula of Barium hydroxide, we have to go to the periodic table and look for the Barium (Ba), which is in group 2 and has an ionic charge of 2+. Hydroxides are not an element that is present in the periodic table is the combination of Oxygen and Hydrogen (OH), and its ionic charge is 1-.

To name this substance, we write the elements that form it, which are Ba OH, then we see the ionic charges that they have, Ba2+ OH 1- and we change these charges giving the 2+ to the OH and the 1- to the Ba. It would look Ba OH₂; we do not write the 1, and as there is a 2, the OH, has to be between brackets so that the final formula is Ba(OH)₂. What we did is balancing the charges of the elements. In other words, we need 2 OH for every Ba. Hydroxides give an electron to balance the Ba ionic charge.

Barium Hydroxide is an ionic compound because ionic compounds are formed by a metal (Ba) and a nonmetal element (OH), ionic compounds are charged, so when they are in an aqueous solution they conduct electricity because their ions move freely in the solution.                                          

5 0
3 years ago
19.3 g of cadmium hydroxide reacted with 15.21 g of hydrobromic acid. How many grams of water can be made?
Alecsey [184]

Answer:

m_{H_2O}=3.384gH_2O

Explanation:

Hello,

In this case, the chemical reaction is:

Cd(OH)_2+2HBr\rightarrow CdBr_2+2H_2O

Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:

n_{H_2O}^{by\ Cd(OH)_2}=19.3gCd(OH)_2*\frac{1molCd(OH)_2}{146.4gCd(OH)_2}*\frac{2molH_2O}{1molCd(OH)_2}=0.264molH_2O\\\\n_{H_2O}^{by\ HBr}=15.21gHBr*\frac{1molHBr}{80.9gHBr}*\frac{2molH_2O}{2molHBr}=0.188molH_2O

In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:

m_{H_2O}=0.188molH_2O*\frac{18gH_2O}{1molH_2O}\\ \\m_{H_2O}=3.384gH_2O

Regards.

4 0
3 years ago
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