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zhenek [66]
3 years ago
14

If you ignore air resistance after an initial force launches a projectile, name all forces acting on it as it moves through the

air. What does this force cause the object to do?
Physics
1 answer:
alekssr [168]3 years ago
8 0

Answer:

Neglecting air resistance, the only force acting on a projectile is gravity.

This force causes the object to accelerate.

Explanation:

As a projectile moves upward, there is a downward force and a downward acceleration due to force of gravity. That is, as the object is moving upward, force of gravity acting on the projectile is causing a steady slowing down of the projectile.

Hence, Gravity is the downward force upon a projectile that influences its vertical motion and causes the parabolic trajectory that is characteristic of projectiles.

From Newton's law of motion, it suggest that force is required to cause an acceleration and not motion. Therefore, force of gravity causes the object to accelerate downwards.

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Inertia is a term that qualitatively describes the ability of a substance to resist changes in its state of motion, while mass gives a quantitative value for inertia
7 0
3 years ago
How much power does it take to lift 70.0 N to 5.0 m high in 5.00 s?
lesantik [10]

Answer:

Power = 70 W

Explanation:

Given that,

Force, F = 70 N

Height, h = 5 m

Time, t = 5 s

We need to find the power of the object. We know that,

Power = work done/time

Put all the values,

P=\dfrac{Fd}{t}\\\\P=\dfrac{70\times 5}{5}\\\\P=70\ W

So, the required power is 70 W.

3 0
3 years ago
A large body collides with a stationary small body from the rear end. How do the bodies behave if the collision is inelastic?.
alexdok [17]
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6 0
3 years ago
An engine absorbs 1749 J from a hot reservoir and expels 539 J to a cold reservoir in each cycle. a. What is the engine’s effici
Masja [62]

Answer:

a)η = 69.18 %

b)W= 1210 J

c)P=3967.21 W

Explanation:

Given that

Q₁ = 1749 J

Q₂ = 539  J

From first law of thermodynamics

Q₁   = Q₂ +W

W=Work out put

Q₂=Heat rejected to the cold reservoir

Q₁ =heat absorb by hot  reservoir

W= Q₁- Q₂

W= 1210 J

The efficiency given as

\eta=\dfrac{W}{Q_1}

\eta=\dfrac{1210}{1749}

\eta=0.6918

η = 69.18 %

We know that rate of work done is known as power

P=\dfrac{W}{t}

P=\dfrac{1210}{0.305}\ W

P=3967.21 W

8 0
3 years ago
Brainliest if correct Question 1 of 10
Artyom0805 [142]

Answer:

B

Explanation:

7 0
2 years ago
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