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OLga [1]
3 years ago
6

Joshua, an editor for the Winston Salem Gazette, edits 1⁄6 of a page in 3 minutes. How long would it take him to edit 3 pages?

Mathematics
1 answer:
quester [9]3 years ago
8 0

Answer:

54

Step-by-step explanation:

If we know that Josh edits at a rate of 1/6 of a page in three minutes... then using the Unit rule... we can determine that he edits 1 whole page 6 times longer than that. By doing that... we find that Josh edits 1 page in 18 minutes. From there... we multiply the time at which it takes him to edit one page (18 minutes) by 3 (pages) to get our answer.

18 x 3 = 54

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7 0
3 years ago
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cricket20 [7]

Answer:

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Answer:
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3 years ago
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8 0
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vlada-n [284]
\bf h=20ln(3t+2)+30\\\\&#10;-------------------------------\\\\&#10;\boxed{a}\\\\&#10;\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30&#10;\\\\\\&#10;h\approx 43.86&#10;\\\\\\&#10;\boxed{b}\\\\&#10;\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)&#10;\\\\\\&#10;\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2&#10;\\\\\\&#10;e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t

\bf \boxed{c}\\\\&#10;\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3  \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}&#10;\\\\\\&#10;\left. \cfrac{dh}{dt}  \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}&#10;\\\\\\&#10;\left. \cfrac{dh}{dt}  \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}
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3 years ago
Read 2 more answers
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