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3 years ago

HELP IM GIVING BRAINLY

Chemistry

1 answer:

Galina-37 [17]3 years ago

4 0

Answer:

250 mL

Explanation:

The second equation is: Molarity 1 x Volume 1 = Molarity 2 x Volume 2

Plug in, solving for Volume 2

Solve

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At high temperatures phosphine (PH_3) dissociates into phosphorus and hydrogen by the following reaction: 4PH3 rightarrow P_4 +

Alex_Xolod [135]

Answer:a)p4=0.75mol

H2=4.5mol

B)PH3=1×10^7mole

P4=0.25×10^7mole

H2=1.5×10^7mole

Time taken for 3mol of phosphine to react is 54 ×10^7s

Explanation:From the balanced chemical equation

4PH3____P4+6H2

From Gay lussac law ,when gases combines

,They do so in a ratio which bear a simple ratio with their products,if gases.

So it means from the equation above

4 mol of PH3 will form 1mol of P4 and 6 mol of H2

Meaning that if 4mol of PH3 gives 1mol of P4

Then 3mol of PH3 will give 1/4 mol or 0.75 mol of P4 .

In the same vein,3mol of PH3 will give 6×3/4 mol of H2= 4.5 Mol of H2

B) molar concentration =mole/volume

Meaning mole=molar concentration ×volume

Molar concentration is given as 5Km/m^3=5000mol/m^3

Volume=2L =2×1000=2000m^3

Nos of moles=5000×2000=10^7moles

So for P4,nos of moles =1/4×10^7=0.25×10^7

ForH2 ,6/4 ×10^7=1.5×10^7 moles

Rate= volume/time

Time taken for reaction will be volume/rate=2000/3.715×10^6

=54×10^7s

5 0

3 years ago

If an 85.0 mL container of helium gas at standard pressure is heated from 20.oC to 91oC and the pressure is increased to 2.8 atm

erastovalidia [21]

Answer: V₂ = 37.71mL

Explanation: To determine the new volume of Helium gas, use the Combined Gas Law, which states the following relationship among pressure, volume and temperature:

$\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

where index 1 relates to the initial state of the gas and index 2 to the final state of the gas.

Temperature is in Kelvin, so:

T = °C + 273

For this situation, standard pressure is 1 atm. Temperatures will be:

T₁ = 20 + 273 = 293 K

T₂ = 91 + 273 = 364 K

Solving:

$V_{2}=\frac{T_{2}P_{1}V_{1}}{P_{2}T_{1}}$

$V_{2}=\frac{364*1*85}{2.8*293}$

$V_{2}=\frac{30940}{820.4}$

$V_{2}=$ 37.71

The new volume of He gas is 37.71 mL.

5 0

3 years ago