Why do atoms always contain the same number of electrons and protons?

Chemistry

2 answers:

katovenus [111]3 years ago

8 0

Answer:

An electron is a negatively charged subatomic particle and a proton is a positively charged subatomic particle. Positive charge(s) attract negative charge(s) and vice versa. The proton and neutron stay together and attract one another to give the atom an overall charge of zero (neutral). Which is the charge of an atom. When there is an unequal number of protons and neutrons an ion is formed. If the number of protons are more than the electron, a positively charged ion called cation is formed. On the other hand, if the number of electrons are more than the protons a negatively charged ion called anion is formed.

docker41 [41]3 years ago

6 0

Answer:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral. ... Chemically, we say that the atoms have formed bonds.

Explanation:

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Consider the following reaction where Kc = 1.80×10-2 at 698 K:2 HI (g) H2 (g) + I2 (g)A reaction mixture was found to contain 0.

Iteru [2.4K]

Answer:

Answer for the given statements: (1) T , (2) F , (3) T , (4) F , (5) F

Explanation:

At the given interval, concentration of HI = $\frac{0.304}{1}M=0.304M$

Concentration of $H_{2}$ = $\frac{5.07\times 10^{-2}}{1}M=5.07\times 10^{-2}M$

Concentration of $I_{2}$ = $\frac{4.57\times 10^{-2}}{1}M=4.57\times 10^{-2}M$

Reaction quotient, $Q_{c}$ , for this reaction = $\frac{[H_{2}][I_{2}]}{[HI]^{2}}$

species inside third bracket represents concentrations at the given interval.

So, $Q_{c}=\frac{(5.07\times 10^{-2})\times (4.57\times 10^{-2})}{(0.304)^{2}}=2.51\times 10^{-2}$

So, the reaction is not at equilibrium.

As $Q_{c}> K_{c}$ therefore reaction must run in reverse direction to reduce $Q_{c}$ and make it equal to $K_{c}$ . That means HI(g) must be produced and $H_{2}$ must be consumed.