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Setler79 [48]
2 years ago
10

Which of these would have particles with the highest kinetic energy?

Chemistry
2 answers:
Eddi Din [679]2 years ago
7 0

Answer:

water vapor

Explanation:

Liquid water molecules have less freedom to move around. While molecules of water vapour have more freedom to move around as there is larger space between the molecules. Hence, the kinetic energy of water molecules is more as compared to the kinetic energy of liquid water

miv72 [106K]2 years ago
6 0

Answer:

water vapor

Explanation:

because gas molecules moves the fastest

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Question 2(Multiple Choice Worth 3 points) What happens to the rate of most reactions as the reaction progresses? The rate remai
Sav [38]

Answer: -

The rate decreases as the concentration of the reactants decreases

Explanation: -

A reaction involves change of the reactants into products.

Initially there is only reactants. So the rate if reaction is high.

After some time there are products. So the amount of reactant is less.

Reactions involve collisions of reactant molecules. As the reactant amount decreases, collisions between the reactants decreases. As such the rate of reaction decreases with the progress of the reaction.

3 0
2 years ago
Which of the following is the best example of how Earth's geosphere interacts with the biosphere?
olga55 [171]

Answer:fffffhhhgffv

Explanation:

6 0
3 years ago
Two common methods to generate an aldehyde is by oxidation of an alcohol and through ozonolysis.
kotykmax [81]

Answer:

<u>a</u><u>.</u><u> </u><u>True</u><u>.</u>

Explanation:

Only primary and secondary alcohols can oxidise to give an aldehyde. But a weak oxidizing agent must be used to prevent formation of a carboxylic acid or ketone.

weak oxidizing agents: Chromyl chloride, silver/oxygen/500°C

take an example of <u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>o</u><u>l</u><u>:</u>

<u>{ \bf{CH _{3} CH_{2}OH \:  \:  \frac{Ag/O_{2} }{500 \degree C}  >  \:  \:CH _{3} CHO}}</u>

<u>{ \sf{CH _{3} CHO \:  \: is \: ethanal}}</u>

<u>B</u><u>y</u><u> </u><u>o</u><u>z</u><u>o</u><u>n</u><u>o</u><u>l</u><u>y</u><u>s</u><u>i</u><u>s</u><u>:</u>

Here, reactants are Ozone gas, Carbon tetrachloride at a temperature (<20°C), ethanoic acid, zinc and water.

take an example of propanol:

if it undergoes ozonolysis, it gives ethanal and methanal.

5 0
2 years ago
Read 2 more answers
A runner competed in a 5-mile run. How many yards did she run?
vfiekz [6]
5 miles are equivalent to 8,800 yards

so b. is the correct answer. plz like and hope it helped
3 0
3 years ago
Consider the following reaction and situations 1 through 10. In the spaces provided, clearly indicate the best response to each
olchik [2.2K]

Answer:

1. C. no change

2. A. increase

3. E. shift to the right

4. A. increase

5. E. shift to the right

6. A. increase

7. F. cannot be determined

8. B increase

9. D. shift to the left

10 F. cannot be determined

Explanation:

<em>According to Le Chaterlier principle, when a reaction is in equilibrium and one of the constraints that affect reactions is applied, the equilibrium will shift so as annul the effects of the constraints.</em>

From the equation: C(s) + H2O(g) ⇌ CO(g) + H2(g),

H is greater than 0, meaning that the system is endothermic, that is energy is absorbed.

1. If the pressure of the system is increased, there would be no change to the system because there are equal number of moles of products and reactants.

2. If H2 concentration is decreased, the equilibrium will shift to the right and more products will be formed. Hence, the concentration of CO will increase.

3. If H2 concentration is decreased, the equilibrium will shift to the right to annul the effects of the decrease in the concentration of a product.

4. If the concentration of H2 is increased, the equilibrium will shift to the left to annul the effects of increased concentration of a product. Hence, more H2O would be formed.

5. If H2 (a product) is removed, and C (a reactant) is added, more of the products will be formed in order to annul the effects of the actions. Hence, equilibrium will shift to the right.

6. If the amount of C (a reactant) is increased, the equilibrium will shift to the right. Hence, more H2 will be formed.

7. The reaction is endothermic, hence an increase in temperature will ordinarily shift the equilibrium to the right. However, the addition of H2 (a product) is supposed to shift the equilibrium to the left. Hence, the effects of simultaneous addition of the two actions become indeterminate.

8. Since the reaction is endothermic, increase in the temperature of the system will shift the equilibrium to the right. Hence, more CO will be formed.

9. If the concentration of H2O (a reactant) is decreased and that of CO (a product) is increased, both actions lead to the equilibrium being shifted to the left.

10. Addition of catalyst to the system will only speed up the rate at which the system reach the equilibrium.

5 0
2 years ago
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