Andre wrote the inequality to plan his time. Describe what 3x + 10 ≤ 30 represent in this inequality.
1 answer:
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The answer is a = 3/4 = 0.75
First get rid of the paranthesis,
Then set the denominators equal:
Then remove the denominators and solve:
Eliminate -12a^2 by adding 12a^2 to both sides:
Take the fourth root of them or take the square root twice:
![\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%20%7Ba%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B81%7D%20%20%20%5C%5C%20%204a%20%3D%203)
Divide both sides by 4:
First get rid of the paranthesis,
Then set the denominators equal:
Then remove the denominators and solve:
Eliminate -12a^2 by adding 12a^2 to both sides:
Take the fourth root of them or take the square root twice:
Divide both sides by 4:
The translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.
In the question, we are asked to translate the given figure 2 units left and 7 units down.
In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.
For any point P(x, y) the given rule says that after translation,
P(x, y) becomes P'(x - 2, y - 7).
The coordinates of the given figure are:
A(3,9), B(5,9), C(5,2), and D(1,4).
After translation, these points can be shown as:
A(3,9) becomes A'(1,2).
B(5,9) becomes B'(3,2).
C(5,2) becomes C'(3,-5).
D(1,4) becomes D'(-1,-3).
Thus, the translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.
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