Question

Select the correct answer from the drop-down menu. Simplify the expression. 3y3 – 2y[4y – y(y – 3)] – [2y(y + 1) – 3y(y2 –1)] =

Answer 1

Answer:

Given the expression: $3y^3-2y[4y-y(y-3)]-[2y(y+1)-3y(y^2-1)]$

The distributive property says that:

$a\cdot (b+c) = a\cdot b+ a\cdot c$

Applying distributive property on the given expression, we have;

$3y^3-2y[4y-y^2+3y]-[2y^2+2y-3y^3+3y]$

again apply the same property we have

$3y^3-8y^2+2y^3-6y^2-[2y^2+2y-3y^3+3y]$

or

$3y^3-8y^2+2y^3-6y^2-2y^2-2y+3y^3-3y$

Like terms are those terms which have same variables to the same power.

Combine like terms;

$8y^3-16y^2-5y$

Therefore, the simplified form of the given expression is,  $8y^3-16y^2-5y$