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oksian1 [2.3K]
3 years ago
12

Can someone tell me the answer and how to do the problem?

Chemistry
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

is tht wht u want

Explanation:

1 grams Sodium is equal to 0.043497607849056 mole.

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What is the difference between mass and weight?
Olin [163]

Explanation:

The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.

7 0
2 years ago
What is the wavelength of light with 2.89 x 10-19 J of energy? (The speed of
Alika [10]

Let's see

\\ \rm\rightarrowtail E=hv

\\ \rm\rightarrowtail E=\dfrac{hc}{\lambda}

  • lambda is wavelength
  • h is Planck constant
  • c is velocity of sound in air
  • E in energy

\\ \rm\rightarrowtail \lambda=\dfrac{hc}{E}

\\ \rm\rightarrowtail \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{2.89\times 10^{-19}}

\\ \rm\rightarrowtail \lambda=6.878\times 10^{-7}m

\\ \rm\rightarrowtail \lambda=68.8\mu m

3 0
1 year ago
Indicate the number of significant figures in the measured number 0.0020 <br> A. 4<br> B. 5<br> C. 2
Sergio [31]

<u>Answer:</u>

The correct answer option is C. 2.

<u>Explanation:</u>

We are given the number '0.0020' and we are to indicate the number of significant figures in the given measured number.

According to the rules of significant figures, numbers that are non-zero, zeros between any two significant numbers and the ending zeros in the decimal position are categorized as significant figures.

Since there is one non-zero number and one ending zero in the decimal position, therefore 0.0020 has 2 significant figures.

6 0
3 years ago
F liquid water runs into an open space within a rock, like a crack, and the temperature drops to the freezing point of water, wh
vodomira [7]

Answer:

b or c is the answer

Explanation:

brainlest plz

4 0
2 years ago
Read 2 more answers
Find the horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40m/s​
vfiekz [6]

To Find :

The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s​.

Solution :

The horizontal range of a projectile is given by :

R = \dfrac{u^2 sin 2\theta}{g} ( Here, g is acceleration due to gravity = 10 m/s² )

Putting all value in above equation :

R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m

Therefore, the horizontal range of projectile is 80 m.

4 0
3 years ago
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