All categories

3 years ago

Who do you think the target market of these advertisements is? Explain.

Physics

1 answer:

ANEK [815]3 years ago

6 0

Answer:

uhhhhhhh wait what

Explanation:

What advertisement

You might be interested in

Is it possible for a circuit to be connected both in series and in parallel?

marshall27 [118]

Hello There!

Well, technically no. It has to be one or the other, it can't be both.

Hope This Helps You!
Good Luck :)

- Hannah ❤

4 0

3 years ago

Collette has a prediction that college students ' immune systems have declined due to the use of hand sanitizers . This idea is

Nataly_w [17]

The idea that "students ' immune systems have declined due to the use of hand sanitizers " is a hypothesis.

The term hypothesis refers to an intelligent guess or idea often based which is subject to scientific investigation via experiments.

A hypothesis may be right or wrong. We can only prove a hypothesis by subjecting it to a series of rigorous experiments.

Thus Collette's idea is a hypothesis.

Learn more: brainly.com/question/18284466

5 0

3 years ago

What would you get if you split a bar magnet in the middle?

ipn [44]

Answer:

I believe it's the first option

5 0

3 years ago

Four copper wires of equal length are connected in series. Their cross-sectional areas are 0.7 cm2 , 2.5 cm2 , 2.2 cm2 , and 3 c

Travka [436]

Answer:

22.1 V

Explanation:

We are given that

$A_1=0.7 cm^2=0.7\times 10^{-4} m^2$

$A_2=2.5 cm^2=2.5\times 10^{-4} m^2$

$A_3=2.2 cm^2=2.2\times 10^{-4} m^2$

$A_4=3 cm^2=3\times 10^{-4} m^2$

Using $1cm^2=10^{-4} m^2$

We know that

$R=\frac{\rho l}{A}$

In series

$R=R_1+R_2+R_3+R_4$

$R=\frac{\rho l}{A_1}+\frac{\rho l}{A_2}+\frac{\rho l}{A_3}+\frac{\rho l}{A_4}$

$R=\frac{\rho l}{\frac{1}{A_1}+\frac{1}{A_2}+\frac{1}{A_3}+\frac{1}{A_4}}$

Substitute the values

$R=\rho A(\frac{1}{0.7\times 10^{-4}}+\frac{1}{2.5\times 10^{-4}}+\frac{1}{2.2\times 10^{-4}}+\frac{1}{3\times 10^{-4}})$

$R=\rho l(2.62\times 10^4)$

$V=145 V$

$I=\frac{V}{R}=\frac{145}{\rho l(2.62\times 10^4)}$

Voltage across the 2.5 square cm wire= $IR=I\times \frac{\rho l}{A_2}$

Voltage across the 2.5 square cm wire= $\frac{145}{\rho l(2.62\times 10^4)}\times \frac{\rho l}{2.5\times 10^{-4}}=22.1 V$

Voltage across the 2.5 square cm wire=22.1 V

6 0

3 years ago

Which statement is true regarding copper's ability to conduct electricity?

zhenek [66]

<span>Copper is a good conductor of electricity because its atoms have a loosely held electron in their outer shell that is able to move freely to other atoms.</span>

7 0

3 years ago

Read 2 more answers