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Hitman42 [59]
3 years ago
7

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!

Physics
1 answer:
astraxan [27]3 years ago
6 0
The answer is A. Trust me!
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A cup of water is warmed from 21 °C to 85 °C. What is the difference between these two temperatures, in kelvins?
Ilya [14]

Answer:

337k

Explanation:

First, let us find the difference between the given two temperatures.

Difference = 85°C - 21°C

                  = 64°C

<u>And now we have to write the temperature in kelvins.</u>

To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.

<u>Let us find it now.</u>

64°C + 273 = 337k

Therefore,

64°C ⇒ <u>337k</u>

8 0
2 years ago
A temperature inversion happens when a _____ air layer traps pollution close to the surface of the earth.
LenaWriter [7]
When warm air layer traps pollution that is within the earth's surface, a temperature inversion usually takes place. In addition, at temperature inversion happens when the cold air overlays the warm air in the troposphere, which does not usually happen since warm air rises and cold air sinks by principle.
8 0
4 years ago
What is the line that joins northen and southren hemisphere of the earth is called a
svp [43]

The line is called equator.

5 0
3 years ago
A car battery with a 12 V emf and an internal resistance of 0.11 Ω is being charged with a current of 56 A. What are (a) the pot
denpristay [2]

Answer:

Part a)

V = 18.16 V

Part b)

P_r = 345 Watt

Part c)

P = 672 Watt

Part d)

V = 5.84 V

Part e)

P_r = 345 Watt

Explanation:

Part a)

When battery is in charging mode

then the potential difference at the terminal of the cell is more than its EMF and it is given as

\Delta V = E + i r

here we have

E = 12 V

i = 56 A

r = 0.11

now we have

\Delta V = 12 + (0.11)(56) = 18.16 V

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

P_r = i^2 r

P_r = 56^2 (0.11)

P_r = 345 W

Part c)

Rate of energy conversion into EMF is given as

P_{emf} = i E

P_{emf} = (56)(12)

P_{emf} = 672 Watt

Now battery is giving current to other circuit so now it is discharging

now we have

Part d)

V = E - i r

V = 12 - (56)(0.11)

V = 12 - 6.16 = 5.84 V

Part e)

now the rate of energy dissipation is given as

P_r = i^2 r

P_r = 56^2 (0.11)

P_r = 345 W

7 0
3 years ago
1. Two forces act on a box as follows: F= 100 N at 02 = 170. and F2= 75 N at
Setler [38]

Answer:

yfv.

Explanation:

7 0
3 years ago
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