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snow_lady [41]
3 years ago
13

Present Value Hoew much shuold be deposited in an account paying 7.2% interest compounded monthly in order to have a balance of

$8000 after 3 years?
Mathematics
1 answer:
jonny [76]3 years ago
6 0

Answer:$6451.6 should be deposited.

Step-by-step explanation:

The principal was compounded monthly. This means that it was compounded 12 times in a year. So

n = 12

The rate at which the principal was compounded is 7.2%. So

r = 7.2/100 = 0.072

It was compounded for 3 years. So

t = 3

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. A is given as $8000 Therefore,

8000 = P (1+0.072/12)^12×3

8000 = P(1+0.006)^36

8000 = P(1.006)^36

P = 8000/1.24

P = $6451.6

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charle [14.2K]
Both triangles area:
4.2 x 8.2 = 34.44

you don’t need to divide by two cause there’s two triangles anyways.

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rectangle:
4.2 x 5.3 = 22.26

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7 0
3 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

We dont know the true proportion, so we use \pi = 0.5, which is when we are are going to need the largest sample size.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2

n = 2401

The minimum sample size is 2401.

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Answer:

x = 111

Step-by-step explanation:

180- 82 -29 is 69 and 180-69 is x which x is equal to 111

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901334 x 2368 = ? I WILL GIVE BRAINLIEST TO A CORRECT ANSWER PLEASE HURRY
aliya0001 [1]

Answer:

901334 x 2368 = 2134358912 is the correct answer

Step-by-step explanation:

I hope this helps you :)

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