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Katena32 [7]
3 years ago
13

Draw a diagram to show how two resistors R1 and R2 are connected in parallel.

Physics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
See attached
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Light always travels in a straight line
Licemer1 [7]

 Light travels in straight lines. Once a light has been produced, it will keep moving in a straight line until it hits something else. Shadows are evidence of light traveling in straight lines. An object blocks light so that it can’t reach the surface where we see the shadow.

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2 years ago
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Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the en
Over [174]
It depends on what that "certain amount" is.
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2 years ago
Which star makes up Orion's knee to your right, or the end of his tunic?
lord [1]

Answer:

Betelgeuse and Rigel

Explanation:

100% correct

7 0
2 years ago
How many days of a diet of 1910 large calories are equivalent to the gravitational energy change from sea level to the top of Mo
andreyandreev [35.5K]

Answer:

0.58 days is needed

Explanation:

Gravitational energy change from a height change equal to 8848 m for a mass of 53 kg is:

m*g*h = 53*9.81*8848 = 4600340.64 J = 4600.34 kJ

4.184 kJ are equivalent to 1 kcal, then:

4.184 kJ / 4600.34 kJ = 1 kcal / x kcal

x = 4600.34/4.184

x = 1099.5 kcal or large calories

The diet is 1910 kcal/day, then you need 1099.5/1910 = 0.58 days

3 0
2 years ago
earth orbits the sun once every 365.25 days. Find the average angular. speed of Earth about the sun.Answer in units of rad/s.
anzhelika [568]

Answer:

1.99\cdot 10^{-7} rad/s

Explanation:

The average angular speed of the Earth about the Sun is given by:

\omega = \frac{2 \pi}{T}

where

2 \pi rad is the total angle corresponding to one revolution of the Earth around the Sun

T is the orbital period of the Earth

The orbital period of the Earth is 365.25 d. We must convert it into seconds first:

T=365.25 d \cdot (24 h/d) \cdot (60 min/h) \cdot (60 s/min)=3.16\cdot 10^7 s

And by substituting into the equation above, we find the average angular speed:

\omega=\frac{2 \pi rad}{3.16\cdot 10^7 m/s}=1.99\cdot 10^{-7} rad/s

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2 years ago
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