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KIM [24]
2 years ago
5

A proton of mass 1.67 x 10-27 kg (the charge of a proton is 1.6 x 10-19 C) enters the region between two parallel plates a

Physics
1 answer:
Zepler [3.9K]2 years ago
3 0
The answer to the question is 72773
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Answer:

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Explanation:

The equation to use to solve this problem is:

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\Delta y is the distance covered

For the particle in free-fall in this problem, we have

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By re-arranging the equation, we can find the distance travelled:

\Delta y = \frac{v_f^2 -v_i^2}{2a}=\frac{(7.9 m/s)^2-0^2}{2(9.8 m/s^2)}=3.2 m

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