A proton of mass 1.67 x 10-27 kg (the charge of a proton is 1.6 x 10-19 C) enters the region between two parallel plates a

Membrane walls of living cells have surprisingly large electric fields across them due to separation of ions. (Membranes are dis

Arturiano [62]

Answer:

Voltage, V = 0.0524 volts

Explanation:

Thickness of the membrane, $d=7.95\ nm=7.95\times 10^{-9}\ m$

Electric field strength, $E=6.6\ MV/m=6.6\times 10^6\ V/m$

We need to find the voltage across it. The relationship between the voltage, electric field and the distance is given by :

$V=E\times d$

$V=6.6\times 10^6\ V/m\times 7.95\times 10^{-9}$

V = 0.0524 volts

So, the voltage across the thick membrane is 0.0524 volts. Hence, this is the required solution.

7 0

3 years ago

assume that the brakes in your car create a constant deceleration regardless of how fast you are going. if you double your drivi

Monica [59]

If that happens to your car and you double the speed then it will take the car longer to come to a complete stop

5 0

3 years ago

Read 2 more answers

What information does a line graph show

ikadub [295]

Line graphs tend to show a change in data over time.

7 0

3 years ago

Need help!!!<br> Physics due tomorrow help, help ,help

Sergio [31]

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

$F_{net}=F_{1}-F_{2}=26-8=14N$

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

$F_{x}=Fsin ($ θ $)= 67sin(73)=64N$

then, as Q(1),

$F_{net}=F_{1}-F_{2}=64-33=31 N$

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

$F_{Tension}=420 N$

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

$F_{x}=Fsin ($ θ $)= 600sin(45)=424.264N$

$F_{y} = F sin ($ θ $)= 600cos45)=424.264N$

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

$F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N$ in east

$F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N$ in south

The total net force for perpendicular forces is calculated from the relation:

$F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N$

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = $tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}$

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, $F_{right}=F_{left}=55N$

7 0

4 years ago

A force does work on an object if a component of the force is called

ivanzaharov [21]

Explanation:

The work done by an object is given by :

$W=Fd\cos \theta$

Here,

F is force

d is displacement

$\theta$ is the angel between F and d.

If the angle between force and displacement is 0, then the work done is equal to, $W=Fd$ .

So, a force does work on an object if a component of the force is parallel to the displacement of the object.

4 0

3 years ago