Answer:
int()
Explanation:
float() is using decimals, so that can't be it, like float(input( "how much does this cost?"))
print() is used to print something, not a user asking, like print("hello")
string() means like a whole, like string( I am good)
By elimination, int() is correct.
Hope this helps!
Answer:
1. Work is a driving force of identity in your life, whether its because it influences you due to the time spent there. Or its truly a passion of yours.
2. Two main aspects of identity development are self-concept and self-esteem
3. Based on you obviously
Hope this helped!
Explanation:
Answer:
0.008
Explanation:
From the question, the parameters given are:
Velocity V = 5 m/s
Pressure = 10 pa
But pressure = F/A
10 = F/A
F = 10A
Substitute all the parameters into the formula below
Coefficient of viscosity (η) = F × r /[AV]
Where
F = tangential force,
r = distance between layers,
A = Area, and
V = velocity
(η) = 10A × 0.004 /[A × 5]
The A will cancel out
(η) = 10 × 0.004 /[5]
(η) = 0.04 /5
(η) = 0.008
Therefore, the coefficient of viscosity of the fluid is 0.008
Answer: downward velocity = 6.9×10^-4 cm/s
Explanation: Given that the
Diameter of the smoke = 0.05 mm = 0.05/1000 m = 5 × 10^-5 m
Where radius r = 2.5 × 10^-5 m
Density = 1200 kg/m^3
Area of a sphere = 4πr^2
A = 4 × π× (2.5 × 10^-5)^2
A = 7.8 × 10^-9 m^2
Volume V = 4/3πr^3
V = 4/3 × π × (2.5 × 10^-5)^3
V = 6.5 × 10^-14 m^3
Since density = mass/ volume
Make mass the subject of formula
Mass = density × volume
Mass = 1200 × 6.5 × 10^-14
Mass M = 7.9 × 10^-11 kg
Using the formula
V = sqrt( 2Mg/ pCA)
Where
g = 9.81 m/s^2
M = mass = 7.9 × 10^-11 kg
p = density = 1200 kg/m3
C = drag coefficient = 24
A = area = 7.8 × 10^-9m^2
V = terminal velocity
Substitute all the parameters into the formula
V = sqrt[( 2 × 7.9×10^-11 × 9.8)/(1200 × 24 × 7.8×10^-9)]
V = sqrt[ 1.54 × 10^-9/2.25×10-4]
V = 6.9×10^-6 m/s
V = 6.9 × 10^-4 cm/s
Answer:
A supercharger is an air compressor that increases the pressure or density of air supplied to an internal combustion engine. This gives each intake cycle of the engine more oxygen, letting it burn more fuel and do more work, thus increasing power.
Explanation:
