Answer:
a) Mechanical efficiency (
)=63.15% b) Temperature rise= 0.028ºC
Explanation:
For the item a) you have to define the mechanical power introduced (Wmec) to the system and the power transferred to the water (Pw).
The power input (electric motor) is equal to the motor power multiplied by the efficiency. Thus, 
.
Then, the power transferred (Pw) to the fluid is equal to the flow rate (Q) multiplied by the pressure jump 
. So 
.
The efficiency is defined as the ratio between the output energy and the input energy. Then, the mechanical efficiency is 
For the b) item you have to consider that the inefficiency goes to the fluid as heat. So it is necessary to use the equation of the heat capacity but in a "flux" way. Calling <em>H</em> to the heat transfered to the fluid, the specif heat of the water and 
the density of the water:
![[tex]H=(5.7-3.6) kW=\rho*Q*c*\Delta T=1000kg/m^3*0.018m^3/s*4186J/(kg \ºC)*\Delta T](https://tex.z-dn.net/?f=%5Btex%5DH%3D%285.7-3.6%29%20kW%3D%5Crho%2AQ%2Ac%2A%5CDelta%20T%3D1000kg%2Fm%5E3%2A0.018m%5E3%2Fs%2A4186J%2F%28kg%20%5C%C2%BAC%29%2A%5CDelta%20T)
[/tex]
Finally, the temperature rise is:
Answer:
FET Transistor
Explanation:
A properly biased Field Effect Transistor will take the audio input and amplify it to drive speakers
Answer:
15 000 000 Ohms
Explanation:
1 Mega Ohm = 1 000 000 Ohms
So,
15 Mega ohms =15 000 000 Ohms
Answer:
Explanation:
(a) we take the free surface of the lake to point 1 and the free surfaces of the storage tank to point 2. We also take the lake surface as the reference level (z1= 0), and thus the potential energy at points 1and 2 are pe1= 0 and pe2= gz2. The flow energy at both points is zero since both 1 and 2 are open to the atmosphere (P1= P2= Paytm). Further, the kinetic energy both points is zero (ke1= ke2= 0) since the water at both locations is essentially stationary. The mass flow rate of water and its potential energy at point 2 kg/s70/s)m070.0)(kg/m1000(33===V&&rmkJ/kg196.0/sm1000kJ/kg1m)20)(m/s(9.8122222===gzpe
Then the rate of increase of the mechanical energy of water becomes kW13.7kJ/kg)6kg/s)(0.1970()0()(22inmech,outreach,fluid mech,===-=-=DpempemeemE&&&&The overall efficiency of the combined pump-motor unit is determined from its definition,67.2%or 0.672
NB:
Please check the attached file for clearer work.
