Answer: Rc = 400 Ω and Rb = 57.2 kΩ
Explanation:
Given that;
VCE = 5V
VCC = 15 V
iC = 25 mA
β = 100
VD₀ = 0.7 V
taking a look at the image; at loop 1
-VCC + (i × Rc) + VCE = 0
we substitute
-15 + ( 25 × Rc) + 5 = 0
25Rc = 10
Rc = 10 / 25
Rc = 0.4 k
Rc = 0.4 × 1000
Rc = 400 Ω
iC = βib
25mA = 100(ib)
ib = 25 mA / 100
ib = 0.25 mA
ib = 0.25 × 1000
ib = 250 μAmp
Now at Loop 2
-Vcc + (ib×Rb) + VD₀ = 0
-15 (250 × Rb) + 0.7 = 0
250Rb = 15 - 0.7
250Rb = 14.3
Rb = 14.3 / 250
Rb = 0.0572 μ
Rb = 0.0572 × 1000
Rb = 57.2 kΩ
Therefore Rc = 400 Ω and Rb = 57.2 kΩ
Answer:
Slot screw driver can be used that way but I wouldn't recommend it
Answer:
A. from zero at the center to maximum at the circumference.
Explanation:
The shear stress describes the process where a body deforms as a result of a part sliding over the other.
The value of shear stress which is induced in the shaft due to the applied couple varies from zero at the center to maximum at the circumference.
The shear stress in a shaft is given by this formula;
τ = Tr/I
where;
τ = shear stress (MPa).
T = applied torque (Nmm).
r = distance from center to stressed surface in the given position (mm).
I = polar moment of Inertia of cross-sectional area (mm).
Width * Length * Thickness * Density = Weight.
48″ * 96″ * . 1875″ * 0.284 lb/in3 = 245 lb.
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To learn more about the software certification refer;
brainly.com/question/11299456
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