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Serggg [28]
3 years ago
14

Number the statements listed below in the order that they would occur in engine operation. Then, label these stages as intake, c

ompression, power, or exhaust.
a. The fuel mixture is ignited by the spark plug, and the resulting explosion forces the piston down in the cylinder.

b. The piston rises and compresses the fuel mixture in the combustion chamber.

c. The exhaust gases left over from the combustion are released from the cylinder. d. A mixture of air and fuel is drawn into the cylinder
Engineering
1 answer:
boyakko [2]3 years ago
6 0

Answer:

d. A mixture of air and fuel is drawn into the cylinder ( Intake)

b. The piston rises and compresses the fuel mixture in the combustion chamber.(compression)

a. The fuel mixture is ignited by the spark plug, and the resulting explosion forces the piston down in the cylinder.(power)

c. The exhaust gases left over from the combustion are released from the cylinder.(exhaust)

Explanation:

The first step in engine operation is called <u>the intake stage</u>, where air mixed with fuel is drawn into the cylinder. This is followed by the <u>compression stage </u>where the piston rises to compress the air mixed with fuel trapped in the chamber.<u>The power stage</u> follows, the air-fuel mixture ignites to cause a spark and small explosion enough to push the piston back down cylinder causing a motion to develop down the piston to the crankshaft.<u>The exhaust stag</u>e is the final one which sees the exhaust gases  released from the cylinder.

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An open vat in a food processing plant contains 500 L of water at 20°C and atmospheric pressure. If the water is heated to 80°C,
tester [92]

Answer:

percentage change in volume is 2.60%

water level rise is 4.138 mm

Explanation:

given data

volume of water V = 500 L

temperature T1 = 20°C

temperature T2 = 80°C

vat diameter = 2 m

to find out

percentage change in volume and how much water level rise

solution

we will apply here bulk modulus equation that is ratio of change in pressure   to rate of change of volume to change of pressure

and we know that is also in term of change in density also

so

E = -\frac{dp}{dV/V}  ................1

And -\frac{dV}{V} = \frac{d\rho}{\rho}   ............2

here ρ is density

and we know ρ  for 20°C = 998 kg/m³

and ρ  for 80°C = 972 kg/m³

so from equation 2 put all value

-\frac{dV}{V} = \frac{d\rho}{\rho}

-\frac{dV}{500*10^{-3} } = \frac{972-998}{998}

dV = 0.0130 m³

so now  % change in volume will be

dV % = -\frac{dV}{V}  × 100

dV % = -\frac{0.0130}{500*10^{-3} }  × 100

dV % = 2.60 %

so percentage change in volume is 2.60%

and

initial volume v1 = \frac{\pi }{4} *d^2*l(i)    ................3

final volume v2 = \frac{\pi }{4} *d^2*l(f)    ................4

now from equation 3 and 4 , subtract v1 by v2

v2 - v1 =  \frac{\pi }{4} *d^2*(l(f)-l(i))

dV = \frac{\pi }{4} *d^2*dl

put here all value

0.0130 = \frac{\pi }{4} *2^2*dl

dl = 0.004138 m

so water level rise is 4.138 mm

8 0
2 years ago
Calculate how large a mass would be necessary to obtain a mechanical noise limit of [Equation] = 1 nG, 1 µG, and 1 mG if the mec
olga55 [171]

Answer:

Mechanical resonance frequency is the frequency of a system to react sharply when the frequency of oscillation is equal to its resonant frequency (natural frequency).

The physical dimension of the silicon is 10kg

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Using the formular, Force, F = 1/2π√k/m

At resonance, spring constant, k = mw² ( where w = 2πf), when spring constant, k = centripetal force ( F = mw²r).

Hence, F = 1/2π√mw²/m = f ( f = frequency)

∴ f = F = mg, taking g = 9.8 m/s²

100 Hz = 9.8 m/s² X m

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6 0
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You can assume there is no pressure drop between the exit of the compressor and the entrance of the turbine. All the power from
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Answer:

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Explanation:

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3 years ago
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rusak2 [61]

Answer:

Automotive Technology Program

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Basically hiring students for hands on training to learn the basics of mechanics.

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