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katrin [286]
2 years ago
15

What is the correct order for the three steps of how a hormone would work

Chemistry
1 answer:
Fudgin [204]2 years ago
8 0

Answer:

answers is -d

Explanation:

,kggc’hnftfj’trudging.ugu,y

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What is the mass of 2.9 moles of calcium? Show all work!
4vir4ik [10]

Answer:

the mass of 2.9 moles of calcium is 116 g

Explanation:

The computation of the mass of 2.9 moles of calcium is shown below

As we know that

Mole = mass ÷  molar mass

where,

Moles be 2.9

And, we know that the molar mass of calcium be 40g/mol

Now put the values to the above formula

2.9 = Mass ÷ 40

So, the mass would be

= 40 × 2.9

=   116 g

Hence, the mass of 2.9 moles of calcium is 116 g

6 0
3 years ago
A graduated cylinder is filled to the 40.00-mL mark with a mineral oil. The masses of the cylinder before and after the addition
castortr0y [4]

Answer:

Firstly, Let's experiment this !

Experiment 1 :

159.446g - 124.966g = 34.48g

34.48g = The mass of Mineral oil.

The density of the mineral oil = M/V = 34.48g/40mL = 0.862g/cm³.

Experiment 2 :

124.966 + 18.173 = 143.139 = The mass of solid + cylinder.

124.966 + 50.952 = 175.918 = The mass of solid + cylinder + Mineral water.

175.918 - 143.139 = 32.779 = The mass of added mineral oil.

Explanation:

Now we have to find the volume of the added mineral oil using the density from experiment 1.

V = 32.779g/0.862g/cm³ = 38.02668213mL

Since we found the volume of the solid, we then have to subtract the added mineral oil volume from the total volume from experiment 1.

Volume of solid = 40-38.02668213 = 1.97331787mL

Density of solid = 18.713g/1.97331787mL = 9.483013499g/cm^3

1.97331787 = (4/3)(3.14)r³

1.97331787*(3/4)(3.14) = .4713338861

.4713338861 = r ³

r = 0.7782328425158433

r = 0.78

Now that's our final answer ! r = 0.78

5 0
3 years ago
What do acids and bases have in common apex?
disa [49]

Both acids and bases produce a part of a water molecule. Bases dissociate hydroxide (–OH) ions and acids, hydrogen (H+) ions that when combined form water. Both are also very corrosive when they are strong enough that they fully dissociate in water.

8 0
3 years ago
Read 2 more answers
A sample of methane gas has a volume of 10 l at a pressure of 1.5 atm and a temperature of 20 °c. what volume does the gas occup
a_sh-v [17]
We can use combined gas laws to solve for the volume of the gas
 \frac{PV}{T}
where P - pressure, V - volume , T - temperature and k - constant
\frac{P1V1}{T1} = \frac{P2V2}{T2}
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
T1 - temperature in Kelvin - 20 °C + 273 = 293 K
T2 - 40 °C + 273 = 313 K
substituting the values 
\frac{1.5 atm*10L}{293 K} =  \frac{0.9 atm*V}{313K}
V = 17.8 L
volume of the gas is 17.8 L 
7 0
3 years ago
At a birthday pool party, the temperature is 28.50°C and the atmospheric pressure is 755.4 mmHg. One of the decoration helium ba
Iteru [2.4K]

Answer:

The volume of the balloon will be 5.11L

Explanation:

An excersise to solve with the Ideal Gases Law

First of all, let's convert the pressure in mmHg to atm

1 atm = 760 mmHg

760 mmHg ___ 1 atm

755.4 mmHg ____ (755.4 / 760) = 0.993 atm

922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm

T° in K = 273 + °C

28.5 °C +273 = 301.5K

26.35°C + 273= 299.35K

P . V = n . R .T

First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K

(0.993atm . 6.25L) / 0.082 . 301.5 = n

0.251 moles = n

Second situation:

1.214 atm . V = 0.251 moles . 0.082 . 301.5K

V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm

V = 5.11L

7 0
3 years ago
Read 2 more answers
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