True or False: An acid is a solution that has an excess of H+ ions.

An object falls from rest at a rate of 10 m/s / s . How fast was it traveling after 5 seconds of fall?

Vesna [10]

Answer:

$v = u + at \\ v = 10 + 9.81 \times 5 \\ v = 59.05m {s}^{ - 1}$

7 0

2 years ago

A single circular loop of wire of radius 0.45 m carries a constant current of 2.4 A. The loop may be rotated about an axis that

Snowcat [4.5K]

Answer:

The magnitude of the uniform magnetic field exerting this torque on the loop is 1.67 T

Explanation:

Given;

radius of the wire, r = 0.45 m

current on the loop, I = 2.4 A

angle of inclination, θ = 36⁰

torque on the coil, τ = 1.5 N.m

The torque on the coil is given by;

τ = NIBAsinθ

where;

B is the magnetic field

Area of the loop is given by;

A = πr² = π(0.45)² = 0.636 m

τ = NIBAsinθ

1.5 = (1 x 2.4 x 0.636 x sin36)B

1.5 = 0.8972B

B = 1.5 / 0.8972

B = 1.67 T

Therefore, the magnitude of the uniform magnetic field exerting this torque on the loop is 1.67 T

8 0

3 years ago

The maximum pressure variations the human ear can withstand are about how much above and below atmospheric pressure?

Crank

The maximum pressure variations the human ear can withstand above and below atmospheric pressure is around 30 pa. the normal atmospheric pressure is around 101325 pa. hence the variation in the maximum pressure for human ear is very small as compared to the atmospheric pressure. if the ear is exposed to a pressure greater than this , it can cause permanent damage to the ear.

4 0

3 years ago

Wheel A has a radius of R and wheel B has a radius of 2R. Wheel A has all the mass at the rim, while wheel B has the mass unifor

azamat

Answer:

Wheel A.

Explanation:

The lesser the moment of inertia, the greater the angular acceleration. Then, the moments of inertia of each wheel are described below:

Wheel A

$I_{A} = M\cdot R^{2}$

Wheel B

$I_{B} = \frac{1}{2}\cdot M \cdot (2\cdot R)^{2}$

$I_{B} = 2\cdot M\cdot R^{2}$

The wheel A accelerates faster in response to the torque.

3 0

2 years ago

Compute the velocity of an electron that has been accelerated through a difference of potential of 100 volts. express your answe

Elodia [21]

The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * $10^{6}$ m/s

Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.

By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

given

charge of electron = 1.6 × $10^{-19}$ C