Fill in the blanks with the terms that complete the sentences about nuclear power plants. Without a critical of fissionable mate
2 answers:
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<h2>Answer:</h2>
(a) 10.00V
(b) 0.5V
<h2>Explanation:</h2>(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;
P = V² / R ------------------(i)
From the question;
P = 5.00W
R = 20.00Ω
Substitute these values into equation (i) as follows;
5.00 = V² / 20.00
V² = 5.00 x 20.00
V² = 100.00
V =
Solve for V;
V = 10.00V
Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V
(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;
V = I x R
=> I = V / R ----------------(ii)
Substitute the values of V and R into equation (ii) as follows;
I = 10.00 / 20.00
I = 0.5A
Therefore, the current through the resistor is 0.5A