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salantis [7]
2 years ago
9

What is the approximate minimum height of a shelf in which this box can fit in the position shown in the picture?

Mathematics
1 answer:
Kay [80]2 years ago
5 0

what is the picture? I would love to help if I knew what the picture looked like.

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For any number n>1, is
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Which expression gives the measure of
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Look at the picture......
Mashcka [7]

Answer:

the coordinates would be (3,6)

5 0
4 years ago
Help please!!!!!
Sergio [31]

Answer:

  • a. image 1

Step-by-step explanation:

<u>Given function:</u>

  • f(x) = 2*3ˣ

<u>Plot two points and check which graph has those:</u>

  • f(0) = 2*3⁰ = 2

and

  • f(1) = 2*3¹ = 6

Points (0, 2) and (1, 6) are correct on the image 1 with blue graph

7 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
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