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ycow [4]
2 years ago
15

ShowWwww workKkkkk pleaseeeeeeeeeee

Physics
1 answer:
Bogdan [553]2 years ago
6 0
Ok so basically you have to look at the work and then look at the work and then it will show
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A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app
zubka84 [21]

Answer:

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

Explanation:

We can use the following equation:

\omega_{f}^{2}=\omega_{i}^{2}-2\alpha \Delta \theta (1)

The angular acceleration is:

a_{tan}=\alpha R

\alpha=\frac{1.9}{0.325}

\alpha=5.85\: rad/s^{2}

and the initial angular velocity is:

\omega_{i}=\frac{v}{R}

\omega_{i}=\frac{27.2}{0.325}

\omega_{i}=83.69\: rad/s

Now, using equation (1) we can find the revolutions of the tire.

0=83.69^{2}-2*25.85 \Delta \theta

\Delta \theta=135.47\: rad

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

I hope it helps you!

6 0
3 years ago
A projectile of mass 1.800 kg approaches a stationary target body at 4.800 m/s. The projectile is deflected through an angle of
Artyom0805 [142]

Answer:

P = 5.22 Kg.m/s

Explanation:

given,

mass of the projectile = 1.8 Kg

speed of the target = 4.8 m/s

angle of deflection = 60°

Speed after collision = 2.9 m/s

magnitude of momentum after collision = ?

initial momentum of the body = m x v

                                                  = 1.8 x 4.8 = 8.64 kg.m/s

final momentum after collision

momentum along x-direction

P_x = m v cos θ

P_x = 1.8 x 2.9 x  cos 60°

P_x = 2.61 kg.m/s

momentum along y-direction

P_y = m v sin θ

P_y = 1.8 x 2.9 x  sin 60°

P_y = 4.52 kg.m/s

net momentum of the body

P = \sqrt{P_x^2 + P_y^2}

P = \sqrt{4.52^2 + 2.61^2}

 P = 5.22 Kg.m/s

momentum magnitude after collision is equal to P = 5.22 Kg.m/s

5 0
3 years ago
Which percentage best describes the visibility of a waxing crescent moon
Rus_ich [418]

Answer:

It be 0,1% - 49.9%

This is because the new moon is 0.0% and the first quarter is 50%.

3 0
2 years ago
A passenger train left station A at 6:00 p.m. Moving with the average speed 45 mph, it arrived at station B at 10:00 p.m. A tran
marishachu [46]
<h2>Average speed of transit train is 60 mph</h2>

Explanation:

Average speed of passenger train = 45 mph

Time taken from station A to station B for passenger train  = 10:00 - 6:00 = 4 hours

Distance between station A to station B = 45 x 4 = 180 miles.

Time taken from station A to station B for transit train  =  4 - 1 = 3 hours

Distance between station A to station B = Average speed of transit train x Time taken from station A to station B for transit train

180 = Average speed of transit train x 3

Average speed of transit train = 60 mph

Average speed of transit train is 60 mph

8 0
3 years ago
1. How does the structure of a hard-boiled egg compare to the crust, mantle, and core structure of Earth? What do the egg's laye
lutik1710 [3]

Answer:

2. Earth layers compare in egg layer it is hard on the outside

Explanation:

6 0
3 years ago
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