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4 years ago

The vector quantity that defines the distance and direction between two positions. It is a change in your position.

Physics

1 answer:

pantera1 [17]4 years ago

5 0

Answer:

Displacement

Explanation:

To describe the change in position you need to indicate the distance between the final and initial positions and the direction in which you moved. The distance is the magnitude.

The quantities that need both magnitude and direction to be described are named vector quantities or, just, vectors.

The vector quantity that defines both the distance and direction between two positions describes the change in your position and is named displacement. For instance, to indicate how you can goe to the supermarket from your house you cannot just say walk 2 miles. You need to indicate the direction; let's say 2 miles North. In this case, the displacement when you goe from your house to the supermarket is 2 miles North. And it is different of the displacement when you comeback from the supermarket to your house, because it would be 2 miles South.

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Consider the following reaction proceeding at 298.15 K: Cu(s)+2Ag+(aq,0.15 M)⟶Cu2+(aq, 1.14 M)+2Ag(s) If the standard reduction

lutik1710 [3]

Answer : The cell potential for this cell 0.434 V

Solution :

The balanced cell reaction will be,

$Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)$

Here copper (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

First we have to calculate the standard electrode potential of the cell.

$E^o_{[Cu^{2+}/Cu]}=0.34V$

$E^o_{[Ag^{+}/Ag]}=0.80V$

$E^o=E^o_{[Ag^{+}/Ag]}-E^o_{[Cu^{2+}/Cu]}$

$E^o=0.80V-(0.34V)=0.46V$

Now we have to calculate the concentration of cell potential for this cell.

Using Nernest equation :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cu^{2+}][Ag]^2}{[Cu][Ag^+]^2}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

Now put all the given values in the above equation, we get:

$E_{cell}=0.46-\frac{0.0592}{2}\log \frac{(1.14)\times (1)^2}{(1)\times (0.15)}$

$E_{cell}=0.434V$

Therefore, the cell potential for this cell 0.434 V

8 0

3 years ago

Behavioral Adaptations: Behavior that animals begin life with that helps them meet their needs is called ________.

Arturiano [62]

I believe the blank would simply be behaviour adaptations. Behavioural adaptations are behaviours that organisms demonstrate to help them better survive and reproduce in a habitat. Hope that helps!!

6 0

3 years ago

Read 2 more answers

4. A 1200 kg car traveling North at 20.0 m/s collides with a 1400 kg car traveling South at 22.0 m/s. The two

Dvinal [7]

Answer:-2.61 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum $p_{o}$ must be equal to the final momentum $p_{f}$ :