Explanation:
yeah that's true.........
Answer:
T = 273 + (-50) = 273 – 50 = 223 K
R = 188.82 J / kg K for CO2
Density (Martian Atmosphere) = P / RT = 900 / 188.92 x 223 = 900 / 42129.16 = 0.0213 kg / 
T = 273 +18 = 291 K, R = 287 J / kg k (for air) P = 101.6 k Pa = 101600 Pa
Density (Earth Atmosphere) = P / RT = 101600 / 287 x 291 = 1.216 kg /
Answer:Solution
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Given:u=−10cm f=20cm (convex lens)
To find: v and image's nature.
Solution: From lens formula
v
1
−
u
1
=
f
1
v
1
+
10
1
=
20
1
Explanation:
initial velocity = 0 = v₍i₎
final velocity = ? = v₍f₎
t = 12 sec
Acceleration = 4m/s²
First we have to find the distance d, for this we use the
formula,
D = v₍i₎t + 1/2at²
D = 0(12) + ½ (4)(12)²
Distance = d = 288 m
Now to find the Vf use the formula,
V₍f₎² = v₍i₎² + 2ad
V₍f₎² = (0)2 + 2(4)(288)
V₍f₎² = 2304
V₍f₎ = 48 m/s
so the velocity at the end of 12 sec is 48 m/s
Three 40w lamp for 6 hours
