Answer:
a)  v = 16.57 m / s, b)  a = 19.6 m / s², d)    N = 1.76 10³ N,     N / W = 3
Explanation:
This exercise looks interesting, but I think you have some problem with the writing, the questions seem a bit disconnected from the initial text.
Let's answer the questions.
a) For this part we can use energy considerations.
Starting point. The upper part of the trajectory indicates that the arm is horizontally
           Em₀ = U = m g h
in this case h = r
Final point. For lower of the trajectory
           Em_f = K = ½ m v²
as they indicate that there is no friction
          Em₀ = em_f
          mgh = ½ m v²
          v = 
let's calculate
         v = 
          v = 16.57 m / s
b) the centripetal acceleration has the formula
            a = v² / r
            a = 16.57² / 14.0
            a = 19.6 m / s²
c) see attached where the diagram is
where N is the normal and w the weight
d) let's use Newton's second law
                N-W = m a
                N - mg = m ar
                N = m (g + a)
let's calculate
                N = 60.0 (9.8 + 19.6)
                N = 1.76 10³ N
the relationship with weight is
               N / W = 1.76 10³/( 60 9.8)
               N / W = 3
normal is three times greater than body weight
e) the answer is reasonable since by Newton's first law the body must continue in a straight line, therefore to change its trajectory a force must be applied to deflect it