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Mekhanik [1.2K]
3 years ago
7

Please help me I will give you 10 points​

Chemistry
1 answer:
Vaselesa [24]3 years ago
5 0

Answer:

red ig

Explanation:

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Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

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