Answer:
Limiting reactant = B2O3
Amount of BCl3 formed = 468 g
Explanation:
The given reaction is:
In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant
Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3
Based on the reaction stoichiometry:
1 mole of B2O3 produces 2 moles of BCl3
Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles
Moles of Bromine produced = 9 moles
<h3>Further explanation</h3>
Given
9 moles of Chlorine gas
Word equation
Required
Moles of Chlorine produced
Solution
We change the word equation into a chemical equation (with a formula)
Aluminum bromide reacts with chlorine gas to produce Aluminum chloride and bromide gas
2AlBr₃+3Cl₂⇒2AlCl₃+3Br₂
moles Cl₂ = 9
Maybe you mean, <em>how many moles of Bromine can we produce?</em>
From equation, mol ratio Cl₂ : Br₂ = 3 : 3, so mol Br₂=mol Cl₂=9 moles
Answer:
Glucose
Explanation:
Glucose is broken down into water and carbon dioxide.
hope this helps! :)
Answer:
Covalent bonding is the sharing of electrons between atoms. In addition, the ionization energy of the atom is too large and the electron affinity of the atom is too small for ionic bonding to occur.
For example: carbon does not form ionic bonds because it has 4 valence electrons, half of an octet.
Explanation:
Answer:
37.85 liters
Explanation:
they need 10 gallons for a month (2.5*4)
after that, convert gallons to liters (conversion to liters= 3.785)
10*3.7585= 37.85
