When forming an ion, this sodium atom will lose 1 electron, as it is the easiest way to form a full shell, as opposed to gaining 7 electrons.
The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1 x 10^6 <span>microliters (mL) in 1 L.
35 kL (1,000 L/ 1kL) (</span>1 x 10^6 microliters / 1 L) = 3.5 x 10^10 microliters<span>
The volume of this pond in microliters is </span><span>3.5 x 10^10 microliters</span>
The number of grams of Ag2SO4 that could be formed is 31.8 grams
<u><em> calculation</em></u>
Balanced equation is as below
2 AgNO3 (aq) + H2SO4(aq) → Ag2SO4 (s) +2 HNO3 (aq)
- Find the moles of each reactant by use of mole= mass/molar mass formula
that is moles of AgNO3= 34.7 g / 169.87 g/mol= 0.204 moles
moles of H2SO4 = 28.6 g/98 g/mol =0.292 moles
- use the mole ratio to determine the moles of Ag2SO4
that is;
- the mole ratio of AgNo3 : Ag2SO4 is 2:1 therefore the moles of Ag2SO4= 0.204 x1/2=0.102 moles
- The moles ratio of H2SO4 : Ag2SO4 is 1:1 therefore the moles of Ag2SO4 = 0.292 moles
- AgNO3 is the limiting reagent therefore the moles of Ag2SO4 = 0.102 moles
<h3> finally find the mass of Ag2SO4 by use of mass=mole x molar mass formula</h3>
that is 0.102 moles x 311.8 g/mol= 31.8 grams
C2H6O + 3O2 —> 2CO2 + 3H2O
Answer is: D. 6.02 x 1023.
Because this is Avogadro constant<span> (the number of </span>constituent particles, in this example atoms of gold<span> that are contained in the </span>amount of substance<span> given by one </span>mole). <span>The </span>mole<span> is the </span>unit of measurement<span> for </span>amount of substance, t<span>he mole is an </span>SI base unit<span>, with the unit symbol </span>mol<span>.</span>
