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jeyben [28]
3 years ago
7

21. Make sure carts are facing so that Velcro strips can stick together when they collide. Keep an extra 250g of mass on the car

t 2 which starts at rest. Change sign on velocity center. Practice giving an initial velocity to cart 1 while cart 2 starts at rest so that after the collision both carts move as a combined object with mass m1 m2. What is the type of collision now you are practicing with two carts
Physics
1 answer:
xeze [42]3 years ago
5 0

Answer:

his type of shock is called inelastic

Explanation:

This exercise is for vehicle crashes, which corresponds to exercise is momentum conservation.

We must begin by defining a system formed by the two cars so that the forces during the crash have been intense and the moment is preserved.

Looking for the moments

initial. Before the crash

           p₀ = m₁ v₁₀

final. After the crash

           p_f = (m₁ + m₂) v

the conservation of the moment is written

           p₀ = p_f

           m₁ v₁₀ = (m₁ + m₂) v

This type of shock is called inelastic and has the characteristics that the kinetic energy is not conserved.

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A hot air balloon competition requires a balloonist to drop a ribbon onto a target on the ground. Initially the hot air balloon
Tpy6a [65]

Answer:

The answer is 3.48 seconds

Explanation:

The kinematic equation

y= y0+V0*t+1/2*a*(t*t)

-50=0+(0)t+1/2(-9.8)*(t*t)

t=3.194 seconds

During ribbons ball,

x=x0+ Vt+1/2*a*(t*t)

x= 0+(15)*(3.194)+1/2*(0)* (3.194*3.194)

x= 47.9157m

So, distance (D) = 100-47.9157= 52.084m

52.084m=0+15(t)+1/2*(0)(t*t)

t=52.084/15=3.472286= 3.48seconds

3 0
3 years ago
Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s.
rjkz [21]

Answer:

Momentum of block B after collision =-50\ kg\ ms^{-1}

Explanation:

Given

Before collision:

Momentum of block A = p_{A1}= -100\ kg\ ms^{-1}

Momentum of block B = p_{B1}= -150\ kg\ ms^{-1}

After collision:

Momentum of block A = p_{A2}= -200\ kg\ ms^{-1}

Applying law of conservation of momentum to find momentum of block B after collision p_{B2}.

p_{A1}+p_{B1}=p_{A2}+p_{B2}

Plugging in the given values and simplifying.

-100-150=-200+p_{B2}

-250=-200+p_{B2}

Adding 200 to both sides.

200-250=-200+p_{B2}+200

-50=p_{B2}

∴ p_{B2}=-50\ kg\ ms^{-1}

Momentum of block B after collision =-50\ kg\ ms^{-1}

6 0
3 years ago
Why in drinking hot water, a thin-bottomed glass is taken?​
taurus [48]

Answer:

beacause it's contracts

Explanation:

when using a large bottomed glass the hot water cools that's why is good to use thin bottomed glass

6 0
3 years ago
What is a risk of using chemical pesticides on crops?
irakobra [83]

Answer:

a. chemical contamination of streams ans rivers

d. adaptation

4 0
3 years ago
A proton traveling to the right enters a region of uniform magnetic field that points into the screen. When the proton enters th
muminat

Answer:

deflected toward bottom of the screen

Explanation:

When entering the region with magnetic field, a magnetic force is exerted on the proton. This force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the proton.

The direction of the force can be determined by using the right-hand rule. We have:

- Index finger: direction of the velocity of the proton --> to the right

- Middle finger: direction of the magnetic field --> into the screen

- Thumb: direction of the magnetic force --> toward bottom of the screen

So, the correct answer is

deflected toward bottom of the screen

8 0
3 years ago
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