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zhannawk [14.2K]
3 years ago
11

A 100-kg astronaut is floating in outer space. If the astronaut throws a 2-kilogram wrench at a speed of 10 meters per second, w

hich best describes her velocity?
Physics
1 answer:
sergey [27]3 years ago
3 0

Since Astronaut and wrench system is isolated in the space and there is no external force on it

So here momentum of the system will remain conserved

so here we can say

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

initially both are at rest

so here plug in all values

0 = 100 v_{1f} + 2\times 10

v_{1f} = -0.20 m/s

so here the astronaut will move in opposite direction and its speed will be equal to 0.20 m/s

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What climate is characterized by constant high temperatures at sea level with an average temperature of 18 °C or higher, and is
kvasek [131]

Correct answer id option C that is tropical.

Tropical Climate is characterized by constant high temperature at sea level with an average temperature of 18°C or higher and is found near the equator.

Areas with tropical climate have high humidity and temperature. Countries in tropical region have high precipitation rate. Tropical climate is also known as equatorial climate. Tropical regions are found near equator. Due to high convection rate, there is abundant rainfall.

3 0
3 years ago
Read 2 more answers
A 40 kg slab rests on a frictionless floor. A 10 kg block rests on top of the slab. The coefficient of static friction between t
Wewaii [24]

Answer:

a) a = 6.1 m/s^2

b)  a = 0.98m/s^2

Explanation:

Mass of slab = 40kg

Mass of block = 10kg

Coefficient of static friction (Us)  = 0.60

Kinetic coefficient (UK)  = 0.40

Horizontal force = 100N

The normal reaction from 40kg slab on 10 kg block = 10*9.81

= 98.1N

Static frictional force = Us*R

= 98.1*0.6

= 58.86N

This is less than the force applied

If 10 kg block will slide on the 40 kg slab,  net force = 100 - kinetic force

Kinetic force (Uk*R) = 0.4*98.1

= 39.28N

= 39N

Net force = 100 -39

= 61N

Recall that F = ma

For 10 kg block

a = F/m

a = 61/10

a = 6.1m/s^2

b) Frictional force on 40 kg slab by 10 kg = 98.1*0.4

= 39.24

= 39N

F = ma

a = F/m

For 40kg slab

a = 39/40

a = 0.98m/s^2

3 0
3 years ago
Tsunami waves are usually created by earthquakes that occur along ? _____ _____
sdas [7]

Answer:

The correct answer is the sea

7 0
4 years ago
A straight 1.20 m long conductor has a 2.00 A current travelling toward the East. Earth's magnetic field in this location is 4.9
KATRIN_1 [288]

Answer:

Force's magnitude=1.176\,10^{-4}\,N

Direction: down (towards the center of the Earth)

Explanation:

Recall that the magnetic force on a conductor of length L carrying a current I in a magnetic field B is given by the equation: F=I\,L\,B in the case the magnetic field B and the direction of the current are at 90 degrees from each other (which is our case). The direction of the force will be given by the "right hand rule" associated with the vector product that defines this force.

Since the current is moving East, and the magnetic field of the Earth goes from North to South, the resultant Force vector will be pointing towards the Earth (and perpendicular to the plane defined by the current's direction and the magnetic field B)

The magnitude of the force, is given by the formula above, and given that all quantities to be considered are is SI units, it will result in Newtons (N):

F=I\,L\,B\\F=2\,*\,1.2\,*\,4.9\,10^{-5}\,N\\F=1.176\,10^{-4}\,N

8 0
4 years ago
An archer shoots an arrow at a 74.0 m distant target, the bull's-eye of which is at same height as the release height of the arr
GuDViN [60]

A. The angle at which the arrow must be released to hit the bull's-eye is 20.7 °

B. The arrow will go over the branch.

<h3>A. How to determine the angle</h3>
  • Range (R) = 74 m
  • Initial velocity (u) = 33 m/s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Angle (θ) = ?

R = u²Sine(2θ) / g

74 = 33² × Sine (2θ) / 9.8

Cross multiply

74 × 9.8 = 33² × Sine (2θ)

725.2 = 1098 × Sine (2θ)

Divide both sides by 1098

Sine (2θ) = 725.2 / 1098

Sine (2θ) = 0.6605

Take the inverse of sine

2θ = Sine⁻¹ 0.6605

2θ = 41.3

Divide both sides by 2

θ = 41.3 / 2

θ = 20.7 °

<h3>B. How to determine if the arrow will go over or under the branch</h3>

To determine if the arrow will go over or under the branch situated mid way, we shall determine the maximum height attained by the arrow. This can be obtained as follow:

  • Initial velocity (u) = 33 m/s
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Angle (θ) = 20.7 °
  • Maximum height (H) = ?

H = u²Sine²θ / 2g

H = [33² × (Sine 20.7)²] / (2 ×9.8)

H = 6.94 m

Thus, the maximum height attained by the arrow is 6.94 m which is greater than the height of the branch (i.e 3.50 m).

Therefore, we can conclude that the arrow will go over the branch

Learn more about projectile motion:

brainly.com/question/20326485

#SPJ1

3 0
2 years ago
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