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zhannawk [14.2K]
3 years ago
11

A 100-kg astronaut is floating in outer space. If the astronaut throws a 2-kilogram wrench at a speed of 10 meters per second, w

hich best describes her velocity?
Physics
1 answer:
sergey [27]3 years ago
3 0

Since Astronaut and wrench system is isolated in the space and there is no external force on it

So here momentum of the system will remain conserved

so here we can say

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

initially both are at rest

so here plug in all values

0 = 100 v_{1f} + 2\times 10

v_{1f} = -0.20 m/s

so here the astronaut will move in opposite direction and its speed will be equal to 0.20 m/s

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Answer:

see below

Explanation:

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Now, correlation.  The definition of correlation in statistics is any statistical relationship between two random variables or data.  This simply means that these two events are connected to one another.  A POSITIVE correlation is when two correlated events move in the same direction as one another.  I have added a graph to help visualize this.  In this problem as the gas is pressed harder, the acceleration increases.  If the pressure on the pedal was decreased, then the acceleration also decreases.  If the pressure on the pedal is constant, the the acceleration is constant.

I hope this helps!

4 0
3 years ago
The boy moving down the hill posses what energy?​
elena-s [515]

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Explanation:

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6 0
2 years ago
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A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie
ale4655 [162]

Explanation:

It is given that,

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Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, B_1=0.5\ T

Final magnetic field, B_2=3\ T

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

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\epsilon=-A\dfrac{d(B)}{dt}

\epsilon=-A\dfrac{B_2-B_1}{t}

\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}

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Induced current in the loop of wire is given by :

I=\dfrac{\epsilon}{R}

I=\dfrac{1.65\times 10^{-3}}{2.4}

I=6.87\times 10^{-4}\ A

So, the induced current in the loop of wire over this time is 6.87\times 10^{-4}\ A. Hence, this is the required solution.

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3 years ago
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