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stiv31 [10]
3 years ago
9

Can someone help me? I am stuck on this question I would mean the world if u helped me! and tysm for the people who helped me!

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0
Believe it’s 150/15 or 50/1 :>
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20 POINTS HELPPPPP
kiruha [24]

For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

We multiply both sides by: (\frac {1} {36}) ^ {3n}

216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}

We divide both sides by 216:

\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}

To divide powers of the same base, we place the same base and subtract the exponents:

216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}

Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

To multiply powers of the same base, we place the same base and add the exponents:

6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1

We know that any number raised to zero is 1, a ^ 0 = 1.

So, for equality to be true:

9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1

Answer:

n = 1

3 0
3 years ago
Read 2 more answers
The degree of the expression 4x^5y^mz is 10. What is the value of m?
geniusboy [140]
The correct answer is 4 :-)
4 0
3 years ago
Read 2 more answers
Simply the following expressions:
Lapatulllka [165]

Answer:

6.    <u> (2x - 1) </u>

      (3x + 2)

8.   <u>     y - 3     </u>

     y² - 3y + 9

Step-by-step explanation:

6.   <u> 2x² + 9x - 5</u>

      3x² + 17x + 10

= <u>(2x - 1) (x + 5)</u>

  3x² + 17x + 10

= <u>(2x - 1)  (x + 5)</u>

  (3x + 2) (x + 5)

= <u> (2x - 1) </u>

  (3x + 2)

8.  <u>y² - 9   </u>

    y³ + 27

= <u> (y + 3) (y - 3)</u>

      y³ + 27

= <u>     (y + 3) (y - 3)     </u>

  (y+3) (y² - 3y + 9)

= <u>     y - 3     </u>

  y² - 3y + 9

5 0
3 years ago
Read 2 more answers
13ab+15ab I’m in 6th grade and I need big help
MatroZZZ [7]

28ab

Hope it helps

4 0
3 years ago
Read 2 more answers
Use the numbers from the original example: $1,000 invested at a 2% interest rate compounded n times per year. Compare the change
damaskus [11]
Given:
P₀ = $1000, the principal
r = 2% = 0.02, the APR

Let the duration be 1 year 
n =  number of compounding intervals per year.
The value after 1 year is
A=P_{0}(1 +  \frac{r}{n} )^{nt} = 1000(1+ \frac{0.02}{n})^{n}

The following table shows the results obtained from the calculator.

     n                   A
------  ------------------
     1   1020.00000
     4   1020.15050
    12   1020.18436
    52  1020.19742
  365  1020.20078


4 0
3 years ago
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