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PtichkaEL [24]
3 years ago
11

this is an area where two tectonic plates move towards each other with one going under the other plate?

Physics
1 answer:
Doss [256]3 years ago
6 0

Answer:Convergent boundaries are areas where plates move toward each other and collide. These are also known as compressional or destructive boundaries. Subduction zones occur where an oceanic plate meets a continental plate and is pushed underneath it. Subduction zones are marked by oceanic trenches.

pLS THANK ME AND VOTE ME BRAINLIEST ME

Explanation:

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Questions Two cyclists, 42 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?

<u><em>Start of Answer:</em></u>

-- When they started, they were 42 miles apart.  When they met, 2 hours later, they were no miles apart.  The distance between them shrank at the rate of 21 miles per hour.  Since they rode directly toward each other, the sum of their individual speeds must have been 21 miles per hour.

-- One biker was two times the speed of the other.  Slower biker: 1 time.  Faster biker: 2 times.  Sum of their speeds:  3 times = 21 miles per hour.  Each 'time' = 7 miles per hour.

-- Slower cycler = 1 time = 7 mi/hr

<em>Faster cycler = 2 times = 14 mi/hr</em>

5 0
3 years ago
An 97 kg climber climbs to the top of Mount Everest, which has a peak height of 8850 m above sea level. What is the climber’s po
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4 0
3 years ago
Can someone explain it with steps?
Anton [14]

Answer:

Option C is the correct answer

Explanation:

Distance travelled by car during reaction time

=15\times0.4\\\\=6m

The car stopped before hitting the animal by 1 m

Distance travelled during deceleration is 21-6-1=14m

Hence by v^2=u^2+2as

We have

0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2

Option C is the correct answer

5 0
3 years ago
Read 2 more answers
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 19.0 m/s when the
german

Answer: 4 s

Explanation:

Given

The ball leaves the hand of student with a speed of u=19\ m/s

When the hand is h=2.5\ m above the ground

Using the equation of motion we can write

h=ut+\dfrac{1}{2}at^2

Substitute the values

\Rightarrow 2.5=-19t+0.5\times 9.8t^2\\\Rightarrow 4.9t^2-19t-2.5=0\\\\\Rightarrow t=\dfrac{19\pm \sqrt{(-19)^2-4\times 4.9\times (-2.5)}}{2\times 19}\\\Rightarrow t=4.0049\quad [\text{Neglecting the negative value of }t]

Thus, the ball will take 4 s to hit the ground.

5 0
3 years ago
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