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SVEN [57.7K]
3 years ago
14

A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.72 x 10^4 rad/s to an angular speed of 5

.42 x 10^4 rad/s. In the process, the bit turns through 1.72 x 10^4 rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 8.42 x 10^4 rad/s, starting from rest?
Physics
1 answer:
Leto [7]3 years ago
4 0

Answer:

The bit take to reach its maximum speed of 8,42 x10^4 rad/s in an amount of 1.097 seconds.

Explanation:

ω1= 1.72x10^4 rad/sec

ω2= 5.42x10^4 rad/sec

ωmax= 8.42x10^4 rad/sec

θ= 1.72x10^4 rad

\alpha = \frac{w2^{2}-w1^{2}  }{2*(\theta2 - \theta1)}

α=7.67 x10^4 rad/sec²

t= ωmax / α

t= 8.42 x10^4 rad/sec  /  7.67 x10^4 rad/sec²

t=1.097 sec

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The inner planets are different from the outer planets mainly because they are:.
amm1812

Answer:

The inner planets are closer to the Sun and are smaller and rockier. The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus , Earth and Mars.

Explanation:

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2 years ago
Determine the volume of a cube whose width is 32.1 cm. Round your answer to the correct number significant figures.
Romashka [77]

The volume of a cube is given by:

V=L^3

where L is the measure of each side (which corresponds to its width, since all sides of a cube are equal).

Plugging the data of the problem, L=32.1 cm, inside the equation, we find the volume:

V=L^3 =(32.1 cm)^3 =33076.2 cm^3

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3 years ago
Why does conduction occur mainly in the lower atmosphere
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4 0
3 years ago
A block of mass m = 150 kg rests against a spring with a spring constant of k = 880 N/m on an inclined plane which makes an angl
weeeeeb [17]

Answer:

b)  k Δx - W cos θ - μ mg cos θ = m a ,  c)  θ = 86.6º, d)  Δx = 1.18 m

Explanation:

a) In the attachment we can see a diagram of the forces in this problem and the coordinate axes for its decomposition.

F is the force applied by the spring, while it is compressed, this force disappears when the block leaves the spring

b) Let's apply Newton's second law for when the spring is compressed

let's use trigonometry to break down the weight

            sin θ = Wₓ / W

            cos θ = W_y / W

             Wₓ = W sin θ

             W_y = W cos θ

Y axis  

               N - W_y = 0

               N = W_y

               N = W cos θ

X axis

           F -Wₓ -fr = ma

the force applied by the spring is given by hooke's law

           F = k Δx

friction force has the expression

           fr = μ N

           fr = μ W cos θ

we substitute

            k Δx - W cos θ - μ mg cos θ = m a           ( 1)

c) If the plane has no friction, what is the angle so that Δx = 0.1m

             

We write the equation 1, with fr = 0 and since the system is still a = 0

            k Δx - W cos θ -0 = 0

            cos θ = \frac{k \Delta x}{ m g}

            cos θ = \frac{880 \ 0.1}{ 150 \ 9.8}

            cos θ = 0.0598

            θ = cos⁻¹ 0.0598

            θ = 86.6º

d) In this part they give the angle θ = 45º and there is no friction, they ask the compression

the acceleration is zero, we substitute in 1

            k Δx - W cos θ - 0 = 0

            Δx = \frac{mg \ cos \  \theta}{k}

            Δx = \frac{ 150 \ 9.8 \ cos45}{880}

            Δx = 1.18 m

7 0
3 years ago
A disk is free to rotate about an axis perpendicular to the disk through its center. If the disk starts from rest and accelerate
garri49 [273]

Answer:

(C) 16 radians

Explanation:

The angular displacement is given by the following equation:

\Delta \theta=\omega_i t+\frac{1}{2}\alpha t^2

Here

\Delta \theta Is the angular displacement of the body at the indicated time (t).

\omega_i Is the angular velocity of the body at the initial moment.

\alpha Is the angular acceleration of the body.

The disk starts from rest, so \omega_i=0

Replacing the given values:

\Delta \theta=\frac{1}{2}(2\frac{radians}{s^2})(4s)^2\\\Delta \theta=16 radians

3 0
3 years ago
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