*CHEMISTRY*
2 answers:
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FeBr₃ ⇒ limiting reactant
mol NaBr = 1.428
<h3>Further explanation</h3>Reaction
2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr
Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)
- FeBr₃
211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :
- Na₂S
186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :
Coefficient ratio from the equation FeBr₃ : Na₂S = 2 : 3, so mol ratio :
So FeBr₃ as a limiting reactant(smaller ratio)
mol NaBr based on limiting reactant (FeBr₃) :
Answer : The volume of consumed are,
L.
Explanation :
The balanced chemical reaction will be:
First we have to calculate the moles of Al.
Molar mass of Al = 27 g/mole
Now we have to calculate the moles of .
From the reaction we conclude that,
As, 4 mole of Al react with 3 moles of
So, 2 mole of Al react with moles of
Now we have to calculate the volume of consumed.
As we know that, 1 mole of substance occupies 22.4 liter volume of gas.
As, 1 mole of occupies 22.4 liter volume of
gas
So, mole of
occupies
liter volume of
gas
Therefore, the volume of consumed are,
L.